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[Leetcode]

作者:互联网

 

 

class Solution {
    public int subtractProductAndSum(int n) {
        int productResult = 1;
        int sumResult = 0;
        do {
            int currentval = n % 10;
            productResult *= currentval;
            sumResult += currentval;
            n /= 10;
        }while(n > 0);
        
        return productResult - sumResult;
    }
}

 

标签:10,do,int,currentval,sumResult,Leetcode,productResult
来源: https://www.cnblogs.com/seako/p/12005148.html