android-插入RawContact与特定的contactid

我正在尝试在具有特定联系人ID的android中创建rawcontact,因此将其链接到具有相同contactid(而不是rawcontactid)的其他rawcontact.

问题是我无法将Contact_ID插入ContentProviderOpertations.
使用以下代码返回“插入失败”

    ArrayList<ContentProviderOperation> ops = new ArrayList<ContentProviderOperation>();
    int id = (int) contactId;

    String condition = Data.RAW_CONTACT_ID + "=?";
    String[] parameters = { "" + id };

    try {

        String accountName = account.name;
        String accountType = account.type;
        ops.add(ContentProviderOperation.newInsert(RawContacts.CONTENT_URI)
                .withValue(RawContacts.ACCOUNT_TYPE, accountType)
                .withValue(RawContacts.ACCOUNT_NAME, accountName).build());
        ops.add(getAccountGroupOperation(account));

        ops.add(ContentProviderOperation.newInsert(Data.CONTENT_URI)
                .withValueBackReference(Data.RAW_CONTACT_ID, 0)
                .withValue(Data.CONTACT_ID, "" + id)
                .withValue(Data.MIMETYPE, StructuredName.CONTENT_ITEM_TYPE)
                .withValue(StructuredName.DISPLAY_NAME, contact.getName())
                .build()); 
        MyApplication.getAppContext().getContentResolver()
                .applyBatch(ContactsContract.AUTHORITY, ops);
    } catch (Exception e) {
        ...
    }

我究竟做错了什么？

解决方法:

可以执行此操作,但操作方式不理想.您可以通过将两个原始联系人ID都添加到AggregationExceptions表(通过将类型设置为TYPE_KEEP_TOGETHER)来使Contacts应用程序加入两个原始联系人

http://developer.android.com/reference/android/provider/ContactsContract.AggregationExceptions.html

标签：contacts,android-contacts,contactscontract,rawcontacts,android
来源： https://codeday.me/bug/20191201/2084346.html