忽略使用XmlSerializer的外部元素
作者:互联网
我正在尝试反序列化XML文档:
<?xml version='1.0' encoding='UTF-8'?>
<eveapi version="2">
<currentTime>2013-07-07 07:24:20</currentTime>
<result>
<rowset name="characters" key="characterID" columns="name,characterID,corporationName,corporationID">
<row name="xxxxx" characterID="1234" corporationName="xxxx" corporationID="1234" />
</rowset>
</result>
<cachedUntil>2013-07-07 07:40:39</cachedUntil>
</eveapi>
我的模型是:
[XmlRoot("rowset")]
public class CharacterList
{
public CharacterList() { Characters = new List<Character>(); }
[XmlElement("row")]
public List<Character> Characters { get; set; }
}
public class Character
{
[XmlElement("name")]
private string name { get; set; }
[XmlElement("characterID")]
private int Id { get; set; }
[XmlElement("corporationName")]
private string corporationName { get; set; }
[XmlElement("corporationID")]
private int corporationId { get; set; }
}
我的反序列化代码是:
XmlRootAttribute xRoot = new XmlRootAttribute();
xRoot.ElementName = "result";
xRoot.IsNullable = true;
var serializer = new XmlSerializer(typeof(Character), xRoot);
var list = (CharacterList) serializer.Deserialize(output);
但是,我得到一个例外:
System.InvalidOperationException: There is an error in XML document (2,2).
具有内部类型:
System.InvalidOperationException: <eveapi xmlns=''> was not expected.
我很确定这是由于不需要的外部信息.有什么办法可以忽略吗?我的另一个想法是,我可以为模式的其余部分编写包装器类,然后忽略我不关心的内容.但是,我希望有一种更简单的方法.我已经坚持了一段时间,任何帮助将不胜感激.
解决方法:
您可以使用XmlReader导航到内部元素,然后从此处使用XmlSerializer:
using (XmlReader reader = XmlReader.Create("c:\\your.xml"))
{
reader.MoveToContent();
reader.ReadToDescendant("rowset");
var serializer = new XmlSerializer(typeof(CharacterList));
var list = (CharacterList)serializer.Deserialize(reader);
}
另请注意,您的模型中还存在一些问题:
>属性应该是公共的.
>使用XmlAttribute代替XmlElement作为属性
>使用typeof(CharacterList)代替typeof(Character)
[XmlRoot("rowset")]
public class CharacterList
{
public CharacterList() { Characters = new List<Character>(); }
[XmlElement("row")]
public List<Character> Characters { get; set; }
}
public class Character
{
[XmlAttribute("name")]
public string name { get; set; }
[XmlAttribute("characterID")]
public int Id { get; set; }
[XmlAttribute("corporationName")]
public string corporationName { get; set; }
[XmlAttribute("corporationID")]
public int corporationId { get; set; }
}
标签:xml-serialization,xml,c 来源: https://codeday.me/bug/20191123/2064751.html