从Xsd.exe使用XmlReader和类反序列化Xml
作者：互联网
好的,我在尝试一些教程的同时尝试学习XmlSerializer遇到了麻烦.我已经执行了所有建议的步骤,但是我的程序未返回任何内容,或者返回null.我创建了一个XML文件,如下所示：
<?xml version='1.0' encoding='UTF-8' ?>
<WeeklyJobs>
<DailyJobs Date = "02/03/2012"/>
<DailyJobs Date = "02/04/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/05/2012" TotalJobs = "1">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/06/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
<DailyJobs Date = "02/07/2012"/>
<DailyJobs Date = "02/08/2012" TotalJobs = "2">
<Jobs>
<Job JobName = "Job Name" Description = "Description"/>
<Job JobName = "Job Name" Description = "Description"/>
</Jobs>
</DailyJobs>
</WeeklyJobs>
然后,我使用xsd.exe生成了.xsd文件,该文件是：
<?xml version="1.0" encoding="utf-8"?>
<xs:schema id="WeeklyJobs" xmlns="" xmlns:xs="http://www.w3.org/2001/XMLSchema" xmlns:msdata="urn:schemas-microsoft-com:xml-msdata">
<xs:element name="WeeklyJobs" msdata:IsDataSet="true" msdata:UseCurrentLocale="true">
<xs:complexType>
<xs:choice minOccurs="0" maxOccurs="unbounded">
<xs:element name="DailyJobs">
<xs:complexType>
<xs:sequence>
<xs:element name="Jobs" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:sequence>
<xs:element name="Job" minOccurs="0" maxOccurs="unbounded">
<xs:complexType>
<xs:attribute name="JobName" type="xs:string" />
<xs:attribute name="Description" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:sequence>
</xs:complexType>
</xs:element>
</xs:sequence>
<xs:attribute name="Date" type="xs:string" />
<xs:attribute name="TotalJobs" type="xs:string" />
</xs:complexType>
</xs:element>
</xs:choice>
</xs:complexType>
</xs:element>
</xs:schema>
创建架构后,我再次使用xsd.exe为我自动生成了以下类：
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
[System.Xml.Serialization.XmlRootAttribute(Namespace = "", IsNullable = false)]
public partial class WeeklyJobs
{
private WeeklyJobsDailyJobs[] itemsField;
/// <remarks/>
[System.Xml.Serialization.XmlElementAttribute("DailyJobs", Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
public WeeklyJobsDailyJobs[] Items
{
get
{
return this.itemsField;
}
set
{
this.itemsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobs
{
private WeeklyJobsDailyJobsJobsJob[][] jobsField;
private string dateField;
private string totalJobsField;
/// <remarks/>
[System.Xml.Serialization.XmlArrayAttribute(Form = System.Xml.Schema.XmlSchemaForm.Unqualified)]
[System.Xml.Serialization.XmlArrayItemAttribute("Job", typeof(WeeklyJobsDailyJobsJobsJob), Form = System.Xml.Schema.XmlSchemaForm.Unqualified, IsNullable = false)]
public WeeklyJobsDailyJobsJobsJob[][] Jobs
{
get
{
return this.jobsField;
}
set
{
this.jobsField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Date
{
get
{
return this.dateField;
}
set
{
this.dateField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string TotalJobs
{
get
{
return this.totalJobsField;
}
set
{
this.totalJobsField = value;
}
}
}
/// <remarks/>
[System.CodeDom.Compiler.GeneratedCodeAttribute("xsd", "2.0.50727.3038")]
[System.SerializableAttribute()]
[System.Diagnostics.DebuggerStepThroughAttribute()]
[System.ComponentModel.DesignerCategoryAttribute("code")]
[System.Xml.Serialization.XmlTypeAttribute(AnonymousType = true)]
public partial class WeeklyJobsDailyJobsJobsJob
{
private string jobNameField;
private string descriptionField;
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string JobName
{
get
{
return this.jobNameField;
}
set
{
this.jobNameField = value;
}
}
/// <remarks/>
[System.Xml.Serialization.XmlAttributeAttribute()]
public string Description
{
get
{
return this.descriptionField;
}
set
{
this.descriptionField = value;
}
}
}
此后,我将.CS文件添加到我的项目中,并使用文本框创建了一个简单的winform,以在反序列化某些xml后显示一些数据.就像我说的那样,程序启动后,TextBox中什么也不显示,也没有抛出异常.这是我的winform：
public partial class Form1 : Form
{
public Form1()
{
InitializeComponent();
}
public string getExample()
{
XmlSerializer serializer = new XmlSerializer(typeof(WeeklyJobs));
WeeklyJobs jobs;
string xml = @"<?xml version = ""1.0""?>"
+ @"<WeeklyJobs>"
+ @"<DailyJobs Date = ""02/03/2012""/>"
+ @"<DailyJobs Date = ""02/04/2012"" TotalJobs = ""2"">"
+ @"<Jobs>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"<Job JobName = ""Job Name"" Description = ""Description""/>"
+ @"</Jobs>"
+ @"</DailyJobs>"
+ @"</WeeklyJobs>";
// Create an XmlTextReader
using (XmlReader reader = XmlReader.Create(new StringReader(xml)))
{
jobs = (WeeklyJobs)serializer.Deserialize(reader);
}
return jobs.Items[0].Date;
}
private void Form1_Load(object sender, EventArgs e)
{
textBox1.Text = getExample();
}
}
我有很多更简单的xml示例可以使用,但是第二次尝试为我的xml添加一些复杂性,但我失败了.我必须弄清楚如何使用这里的xml.感谢您的帮助！感谢大家！
解决方法:
好的,第一个问题是XmlSerializer构造函数正在引发未处理的异常,但是某种程度上它被吞噬了.这解释了为什么文本框为空.我将调试器设置为在所有CLR异常上均中断,并发现构造函数引发了InvalidOperationException-显然是在代码生成过程中：
Unable to generate a temporary class (result=1).
error CS0030: Cannot convert type ‘DeleteMe.WeeklyJobsDailyJobsJobsJob[]’ to ‘DeleteMe.WeeklyJobsDailyJobsJobsJob’
error CS0029: Cannot implicitly convert type ‘DeleteMe.WeeklyJobsDailyJobsJobsJob’ to ‘DeleteMe.WeeklyJobsDailyJobsJobsJob[]’
(构造函数还抛出了FileNotFound异常,但它也可以处理该异常,因此您可以忽略它.)
似乎问题出在锯齿状阵列中-您是否将一维阵列更改为锯齿状阵列？当然,该错误消息向我指出了这个方向,但是我也从未在xsd生成的代码中见过锯齿状的数组,因此它看起来很可疑.我将两次出现的WeeklyJobsDailyJobsJobsJob [] []更改为WeeklyJobsDailyJobsJobsJob [],该应用程序运行正常.
顺便说一句,您应该使用DateTime作为日期,但是XML序列化器不支持可变日期格式(请参见https://stackoverflow.com/a/1118855/385844).如果您无法控制源,则最好将字符串转换为日期,然后再将其存储在数据库中或任何位置.
标签：xmlreader,deserialization,xml,c 来源： https://codeday.me/bug/20191121/2053387.html