android-堆栈交换API发布方法
作者:互联网
我正在尝试使用android中的stackexchange api投票解决问题.使用网址
https://api.stackexchange.com/2.2/questions/ {questionID} / upvote
但在日志中它只显示了这样的内容
org.apache.http.message.BasicHttpResponse@33b2c539
用于支持问题的API链接是
https://api.stackexchange.com/docs/upvote-question
当我尝试从api链接其工作,但不与代码.
在下面的代码下面找到:
字符串url =“ https://api.stackexchange.com/2.2/questions/” questionId“ / upvote”;
HttpClient httpClient = new DefaultHttpClient();
HttpPost httpPost = new HttpPost(url.toString());
List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(2);
nameValuePair.add(new BasicNameValuePair("key", key));
nameValuePair.add(new BasicNameValuePair("access_token", accessToken));
try {
httpPost.setEntity(new UrlEncodedFormEntity(nameValuePair));
} catch (UnsupportedEncodingException e) {
e.printStackTrace();
}
// making request
try {
response = httpClient.execute(httpPost);
Log.d("Http Post Response:", response.toString());
} catch (ClientProtocolException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
解决方法:
得到了解决方案.
我们应该传递5个参数来投票.
List<NameValuePair> nameValuePair = new ArrayList<NameValuePair>(5);
nameValuePair.add(new BasicNameValuePair("key", key));
nameValuePair.add(new BasicNameValuePair("access_token", accessToken));
nameValuePair.add(new BasicNameValuePair("filter", "default"));
nameValuePair.add(new BasicNameValuePair("site", "stackoverflow"));
nameValuePair.add(new BasicNameValuePair("preview", "false"));
另外,http响应为JSON格式(预期),但为Gzip类型.
我们需要通过将数据发送到GZIPInputStream来解码响应,并以UTF-8解码以读取它. (在api文档中未提及)
GZIPInputStream gin = new GZIPInputStream(entity.getContent());
InputStreamReader ss = new InputStreamReader(gin, "UTF-8");
BufferedReader br = new BufferedReader(ss);
String line = "", data="";
while((line=br.readLine())!=null){
data+=line;
}
标签:http-post,stackexchange-api,android 来源: https://codeday.me/bug/20191120/2043867.html