带有多个具有匹配列的数据集的相关矩阵热图
作者:互联网
如果我们有三个数据集:
X = pd.DataFrame({"t":[1,2,3,4,5],"A":[34,12,78,84,26], "B":[54,87,35,25,82], "C":[56,78,0,14,13], "D":[0,23,72,56,14], "E":[78,12,31,0,34]})
Y = pd.DataFrame({"t":[1,2,3,4,5],"A":[45,24,65,65,65], "B":[45,87,65,52,12], "C":[98,52,32,32,12], "D":[0,23,1,365,53], "E":[24,12,65,3,65]})
Z = pd.DataFrame({"t":[1,2,3,4,5],"A":[14,96,25,2,25], "B":[47,7,5,58,34], "C":[85,45,65,53,53], "D":[3,35,12,56,236], "E":[68,10,45,46,85]})
其中“ t”是一个索引.
只是轴看起来像这样:
解决方法:
X = pd.DataFrame({"t":[1,2,3,4,5],"A":[34,12,78,84,26], "B":[54,87,35,25,82], "C":[56,78,0,14,13], "D":[0,23,72,56,14], "E":[78,12,31,0,34]})
Y = pd.DataFrame({"t":[1,2,3,4,5],"A":[45,24,65,65,65], "B":[45,87,65,52,12], "C":[98,52,32,32,12], "D":[0,23,1,365,53], "E":[24,12,65,3,65]})
Z = pd.DataFrame({"t":[1,2,3,4,5],"A":[14,96,25,2,25], "B":[47,7,5,58,34], "C":[85,45,65,53,53], "D":[3,35,12,56,236], "E":[68,10,45,46,85]})
catted = pd.concat([d.set_index('t') for d in [X, Y, Z]], axis=1, keys=['X', 'Y', 'Z'])
catted = catted.rename_axis(['Source', 'Column'], axis=1)
corrmat = catted.corr()
f, ax = plt.subplots()
sns.heatmap(corrmat, vmax=.8, square=True)
sources = corrmat.columns.get_level_values(0)
for i, source in enumerate(sources):
if i and source != sources[i - 1]:
ax.axhline(len(sources) - i, c="w")
ax.axvline(i, c="w")
f.tight_layout()
对评论的回应:
我更改了X,Y和Z的t列
X = pd.DataFrame({"t":[1,2,3,4,5],"A":[34,12,78,84,26], "B":[54,87,35,25,82], "C":[56,78,0,14,13], "D":[0,23,72,56,14], "E":[78,12,31,0,34]})
Y = pd.DataFrame({"t":[6,7,8,9,10],"A":[45,24,65,65,65], "B":[45,87,65,52,12], "C":[98,52,32,32,12], "D":[0,23,1,365,53], "E":[24,12,65,3,65]})
Z = pd.DataFrame({"t":[11,12,13,14,15],"A":[14,96,25,2,25], "B":[47,7,5,58,34], "C":[85,45,65,53,53], "D":[3,35,12,56,236], "E":[68,10,45,46,85]})
catted = pd.concat([d.set_index('t') for d in [X, Y, Z]], axis=1, keys=['X', 'Y', 'Z'])
catted = catted.rename_axis(['Source', 'Column'], axis=1)
corrmat = catted.corr()
f, ax = plt.subplots()
sns.heatmap(corrmat, vmax=.8, square=True)
sources = corrmat.columns.get_level_values(0)
for i, source in enumerate(sources):
if i and source != sources[i - 1]:
ax.axhline(len(sources) - i, c="w")
ax.axvline(i, c="w")
f.tight_layout()
现在再说一次,但我改为reset_index
X = pd.DataFrame({"t":[1,2,3,4,5],"A":[34,12,78,84,26], "B":[54,87,35,25,82], "C":[56,78,0,14,13], "D":[0,23,72,56,14], "E":[78,12,31,0,34]})
Y = pd.DataFrame({"t":[6,7,8,9,10],"A":[45,24,65,65,65], "B":[45,87,65,52,12], "C":[98,52,32,32,12], "D":[0,23,1,365,53], "E":[24,12,65,3,65]})
Z = pd.DataFrame({"t":[11,12,13,14,15],"A":[14,96,25,2,25], "B":[47,7,5,58,34], "C":[85,45,65,53,53], "D":[3,35,12,56,236], "E":[68,10,45,46,85]})
catted = pd.concat([d.reset_index(drop=True) for d in [X, Y, Z]], axis=1, keys=['X', 'Y', 'Z'])
catted = catted.rename_axis(['Source', 'Column'], axis=1)
corrmat = catted.corr()
f, ax = plt.subplots()
sns.heatmap(corrmat, vmax=.8, square=True)
sources = corrmat.columns.get_level_values(0)
for i, source in enumerate(sources):
if i and source != sources[i - 1]:
ax.axhline(len(sources) - i, c="w")
ax.axvline(i, c="w")
f.tight_layout()
标签:pandas,seaborn,correlation,python,numpy 来源: https://codeday.me/bug/20191112/2023684.html