其他分享
首页 > 其他分享> > 春季-没有字符串参数构造函数/工厂方法从字符串值反序列化(‘1074’)

春季-没有字符串参数构造函数/工厂方法从字符串值反序列化(‘1074’)

作者:互联网

我是Spring DataJPA REST项目的新手,我试图通过具有OneToOne单向关系的引用EmployerType进行添加或编辑Employer.任务很简单,但我遇到了麻烦.当我尝试添加或编辑数据时,出现此错误:

org.springframework.http.converter.HttpMessageNotReadableException:
Could not read document: Can not construct instance of
tr.mis.domain.EmployerType: no String-argument constructor/factory
method to deserialize from String value (‘1074’) at [Source:
java.io.PushbackInputStream@6d856887; line: 1, column: 609] (through
reference chain: tr.mis.domain.Employer[“employerType”]); nested
exception is com.fasterxml.jackson.databind.JsonMappingException: Can
not construct instance of tr.mis.domain.EmployerType: no
String-argument constructor/factory method to deserialize from String
value (‘1074’)

以下是有关类的信息.

@Entity
@Table(name = "employer")
public class Employer implements Serializable  {
    @GenericGenerator(
            name = "wikiSequenceGenerator",
            strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator",
            parameters = {
                    @Parameter(name = "sequence_name", value = "WIKI_SEQUENCE"),
                    @Parameter(name = "initial_value", value = "1000"),
                    @Parameter(name = "increment_size", value = "1")
            }
    )
    @Id
    @GeneratedValue(generator = "wikiSequenceGenerator")
    private Long employerId;
    private String uid;
    private String name;
    private String address;
    private String headName;

    //@JsonIgnore
    @OneToOne(cascade = CascadeType.ALL, fetch = FetchType.EAGER)
   // @PrimaryKeyJoinColumn
    @JoinColumn(name = "employer_type_id")
    private EmployerType employerType;

    //Getters and Setters

EmployerType类

 @Entity
    @Table(name = "employertype")

    public class EmployerType {
        @GenericGenerator(
                name = "wikiSequenceGenerator",
                strategy = "org.hibernate.id.enhanced.SequenceStyleGenerator",
                parameters = {
                        @Parameter(name = "sequence_name", value = "WIKI_SEQUENCE"),
                        @Parameter(name = "initial_value", value = "1000"),
                        @Parameter(name = "increment_size", value = "1")
                }
        )
        @Id
        @GeneratedValue(generator = "wikiSequenceGenerator")

        private Long employerTypeId; 
        private String uid; 
        private String employerTypeName;

    //Getters and Setters

休息控制器

@RequestMapping(value = "/employers", method = RequestMethod.PUT)
    public Employer updateEmployer(@RequestBody Employer employer) {

        return employerRepository.save(employer);

    }

解决方法:

我通过在EmployerType类中添加String构造函数来解决此问题.

 public EmployerType(String employerTypeName) {
        // TODO Auto-generated constructor stub
    }

标签:spring-rest,spring-boot,spring-data-jpa,spring,spring-mvc
来源: https://codeday.me/bug/20191025/1927286.html