c-有关仅正确使用设置器和变量的问题
作者:互联网
我目前的编程工作遇到问题.我觉得我似乎已经很接近正确了,但是有些问题了.我知道我必须做一些不同的事情才能使程序正确运行,因为它目前无法正常工作,但是我不确定它是什么.
我特别在努力使用单个私有变量来同时产生两种温度.
这是作业:
Make a Temperature class. The class should have a function for setting the temperature in Fahrenheit and function for setting a temperature in Celsius. Keep only one data member in the private section for storing the temperature. Create a function for obtaining the in Fahrenheit and a function for obtaining the temperature in Celsius. Test each function thoroughly with a driver.
F = (9/5)C + 32, C = (5/9)(F – 32)
当前代码:
#include<iostream>
using namespace std;
class Temperature
{
private:
double temperature;
public:
void set_fahrenheit(double f)
{
temperature = f;
}
void set_celsius(double c)
{
temperature = c;
}
double get_fahrenheit()
{
return temperature;
}
double get_celsius()
{
return temperature;
}
double converter(double temperature)
{
if (temperature = f)
{
return (9/5)*temperature + 32;
}
else if (temperature = c))
{
return (5/9)*(temperature - 32;
}
}
};
int main()
{
Temperature Temp1;
double temperaturetemp;
string response;
cout << "Would you like to convert a Celsius temperature to Fahrenheit or convert a Fahrenheit temperature to Celsius? (Enter C2F or F2C respectively)" << endl;
cin >> response;
cout << "Please enter the temperature you would like to convert in degrees" << endl;
cin >> temperaturetemp;
if (response == "C2F"){Temp1.set_fahrenheit(temperaturetemp);}
else if (response == "F2C"){Temp1.set_celsius(temperaturetemp);}
cout << Temp1.converter(temperaturetemp);
}
解决方法:
只需使用一个特定的单位内部存储温度,最好是Kelvin1 IMO(因为它是标准的SI物理单位).
将温度设置为华氏度或摄氏度时,请进行必要的计算.
也不要使用整数除法来表示分数:
(5/9)将结果为0整数除,它应该是(5.0 / 9.0)才能获得有效的double值.
与9/5相同,因为整数除法将得出1.
您的代码的其他问题:
>在函数双转换器(双温度)中,您尝试使用f,f不在此范围内
>在同一函数中,您有一个名为temperature的参数,该参数以相同的名称遮盖了成员变量
1)0K = -459,67F / 0K = -273.15°C
标签:c,setter,getter-setter,converters 来源: https://codeday.me/bug/20191014/1911839.html