Android中同时显示多个警报

我被困在这个问题上.我已经阅读了许多关于堆栈溢出的解决方案,但是没有一个解决了我的问题.

这是我的代码：
在我的主要活动中,我写道：

    this.context = this;
    Intent alarm = new Intent(this.context, AlarmManager.class);
    boolean alarmRun = (PendingIntent.getBroadcast(this.context,0,alarm, PendingIntent.FLAG_NO_CREATE) != null);
    if (alarmRun == false){
          PendingIntent pending = PendingIntent.getBroadcast(this.context, 0, alarm, 0);
          AlarmManager alarmMgr = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
                    alarmMgr.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP, SystemClock.elapsedRealtime(), 15000, pending);
            }

因此,第一次打开该应用程序时,将调用Broadcast Receiver,即AlarmManager.java.
这是我在“警报管理器”中所做的操作：
在我的onReceive中-

AlarmDB db = new AlarmDB (context);

List<Alarm> alarms = db.getAlarm();

if(alarms != null)
{
    for (Alarm alarm : alarms)
    {
         Calendar calendar = Calendar.getInstance();
         final int nowHour = Calendar.getInstance().get(Calendar.HOUR_OF_DAY);
         final int nowMinute = Calendar.getInstance().get(Calendar.MINUTE);
         final int nowDay = Calendar.getInstance().get(Calendar.DAY_OF_WEEK);

         calendar.set(Calendar.HOUR_OF_DAY, Integer.parseInt(alarm.getAlarmHour()));
         calendar.set(Calendar.MINUTE, Integer.parseInt(alarm.getStartTimeMinute()));
         calendar.set(Calendar.SECOND, 00);

          PendingIntent pIntent = createPendingIntent(context, alarm);

          if (!(Integer.parseInt(alarm.getAlarmHour()) < nowHour) && !(Integer.parseInt(alarm.getAlarmHour()) == nowHour && Integer.parseInt(alarm.getStartTimeMinute()) <= nowMinute)) 
          {
                 AlarmManager alarmMgr = (AlarmManager)c.getSystemService(Context.ALARM_SERVICE);
                 if (android.os.Build.VERSION.SDK_INT >= android.os.Build.VERSION_CODES.KITKAT) 
                 {
                       alarmMgr.setExact(AlarmManager.RTC_WAKEUP, calendar.getTimeInMillis(), pIntent);
                  } else {
                        alarmMgr.set(AlarmManager.RTC_WAKEUP, calendar.getTimeInMillis(), pIntent);
                  }
          }
      }
}

这是我单独制作的createPendingIntent方法：

private static PendingIntent createPendingIntent(Context context, Alarm m) {
        Intent i = new Intent(context, AlarmService.class);
        i.putExtra(ID, m.getID());
        i.putExtra(NAME, m.getMedName());

        return PendingIntent.getService(context, m.getID(), i, PendingIntent.FLAG_UPDATE_CURRENT);
    }

因此,每当当前时间与数据库中的时间匹配时,就会通过AlarmManager活动中的服务触发意图.请注意,在调用getService时,请求代码是数据库中的唯一ID.我的问题是,尽管我使用的是唯一的ID,但每次同时触发2个或更多警报时,只有其中一个成功触发.那我该怎么做呢？

解决方法:

if (alarmRun == false){
          PendingIntent pending = PendingIntent.getBroadcast(this.context, 0, alarm, 0);
          AlarmManager alarmMgr = (AlarmManager) getSystemService(Context.ALARM_SERVICE);
                    alarmMgr.setRepeating(AlarmManager.ELAPSED_REALTIME_WAKEUP, SystemClock.elapsedRealtime(), 15000, pending);
            }

调用setRepeating将导致以15000毫秒的间隔多次触发BroadcastReceiver.请改用setExact.

标签：android,android-alarms
来源： https://codeday.me/bug/20191013/1910525.html