c-通过串联另一个char *来初始化const char *

我想重构：

const char* arr = 
  "The "
  "quick "
  "brown";

变成类似：

const char* quick = "quick ";
const char* arr = 
  "The "
  quick
  "brown";

因为在许多其他地方都使用了字符串“ quick”.理想情况下,我只需要能够使用const基本类型来做到这一点,所以不需要字符串.做这个的最好方式是什么？

解决方法:

以答案的形式汇编评论：

>使用宏.

#define QUICK "quick "

char const* arr = "The " QUICK "brown";

>使用std：string.

std::string quick = "quick ";
std::string arr = std::string("The ") + quick + "brown";

工作代码：

#include <iostream>
#include <string>

#define QUICK "quick "

void test1()
{
   char const* arr = "The " QUICK "brown";
   std::cout << arr << std::endl;
}

void test2()
{
   std::string quick = "quick ";
   std::string arr = std::string("The ") + quick + "brown";
   std::cout << arr << std::endl;
}

int main()
{
   test1();
   test2();
}

输出：

The quick brown
The quick brown

标签：c,concatenation,initialization,const-char
来源： https://codeday.me/bug/20191013/1907947.html