c-g如何不报告给定代码的错误？

这是我对why is elapsedtime giving me an output of 1?的回答的继续

我能够使用g 4.7.3成功编译并构建以下程序.

#include <iostream>
using namespace std;

int elapsedtime(int time1, int time2)
{
   return (time2-time1);
}

int main()
{
   int time1;
   int time2;
   cin >> time1 >> time2;
   cout << "Your elapsed time is " << elapsedtime <<endl;
}

main中最后一行的意图是：

   cout << "Your elapsed time is " << elapsedtime(time1, time2) <<endl;

g如何能够无错误地编译第一个版本？

解决方法:

std :: ostream具有运算符<< (布尔),并且在标准下,函数名称可以隐式转换为布尔(通过函数到指针的转换以及布尔转换).相关语言为(§4[conv] /p1,§4.3 [conv.func],§4.12[conv.bool])：

A standard conversion sequence is a sequence of standard conversions
in the following order:

• Zero or one conversion from the following set: lvalue-to-rvalue conversion, array-to-pointer conversion, and function-to-pointer conversion.
• Zero or one conversion from the following set: integral promotions, floating point promotion, integral conversions, floating point conversions, floating-integral conversions, pointer conversions, pointer to member conversions, and boolean conversions.
• Zero or one qualification conversion.

An lvalue of function type T can be converted to a prvalue of type
“pointer to T.” The result is a pointer to the function.

A prvalue of arithmetic, unscoped enumeration, pointer, or pointer to
member type can be converted to a prvalue of type bool. A zero
value, null pointer value, or null member pointer value is converted
to false; any other value is converted to true.

标签：c,g
来源： https://codeday.me/bug/20191012/1899947.html