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LeetCode 1212. Team Scores in Football Tournament

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Table: Teams

+---------------+----------+
| Column Name   | Type     |
+---------------+----------+
| team_id       | int      |
| team_name     | varchar  |
+---------------+----------+
team_id is the primary key of this table.
Each row of this table represents a single football team.

 

Table: Matches

+---------------+---------+
| Column Name   | Type    |
+---------------+---------+
| match_id      | int     |
| host_team     | int     |
| guest_team    | int     | 
| host_goals    | int     |
| guest_goals   | int     |
+---------------+---------+
match_id is the primary key of this table.
Each row is a record of a finished match between two different teams. 
Teams host_team and guest_team are represented by their IDs in the teams table (team_id) and they scored host_goals and guest_goals goals respectively.

 

You would like to compute the scores of all teams after all matches. Points are awarded as follows:

Write an SQL query that selects the team_id, team_name and num_points of each team in the tournament after all described matches. Result table should be ordered by num_points (decreasing order). In case of a tie, order the records by team_id (increasing order).

The query result format is in the following example:

Teams table:
+-----------+--------------+
| team_id   | team_name    |
+-----------+--------------+
| 10        | Leetcode FC  |
| 20        | NewYork FC   |
| 30        | Atlanta FC   |
| 40        | Chicago FC   |
| 50        | Toronto FC   |
+-----------+--------------+

Matches table:
+------------+--------------+---------------+-------------+--------------+
| match_id   | host_team    | guest_team    | host_goals  | guest_goals  |
+------------+--------------+---------------+-------------+--------------+
| 1          | 10           | 20            | 3           | 0            |
| 2          | 30           | 10            | 2           | 2            |
| 3          | 10           | 50            | 5           | 1            |
| 4          | 20           | 30            | 1           | 0            |
| 5          | 50           | 30            | 1           | 0            |
+------------+--------------+---------------+-------------+--------------+

Result table:
+------------+--------------+---------------+
| team_id    | team_name    | num_points    |
+------------+--------------+---------------+
| 10         | Leetcode FC  | 7             |
| 20         | NewYork FC   | 3             |
| 50         | Toronto FC   | 3             |
| 30         | Atlanta FC   | 1             |
| 40         | Chicago FC   | 0             |
+------------+--------------+---------------+

 

简要翻译:

两张表:队伍表和比赛表。统计队伍积分,胜3分,平1分,负0分,查询个队伍排名榜,查询结果先按积分降序,然后按team_id升序排列。

 

建表语句:

CREATE TABLE Teams (
  team_id INT ,
  team_name VARCHAR (20)
) ;

CREATE TABLE Matches (
  match_id INT ,
  host_team INT ,
  guest_team INT ,
  host_goals  INT,
  guest_goals INT
) ;

INSERT INTO Teams (team_id, team_name) 
VALUES
  (10, 'Leetcode FC') ;
  
INSERT INTO Teams (team_id, team_name) 
VALUES
  (20, 'NewYork FC') ;

INSERT INTO Teams (team_id, team_name) 
VALUES
  (30, 'Atlanta FC') ;
  
INSERT INTO Teams (team_id, team_name) 
VALUES
  (40, 'Chicago FC') ;
  
INSERT INTO Teams (team_id, team_name) 
VALUES
  (50, 'Toronto FC') ;

INSERT INTO Matches (
  match_id,
  host_team,
  guest_team,
  host_goals,
  guest_goals
) 
VALUES
  (1, 10, 20, 3, 0) ;

INSERT INTO Matches (
  match_id,
  host_team,
  guest_team,
  host_goals,
  guest_goals
) 
VALUES
  (2, 30, 10, 2, 2) ;

INSERT INTO Matches (
  match_id,
  host_team,
  guest_team,
  host_goals,
  guest_goals
) 
VALUES
  (3, 10, 50, 5, 1) ;
  
INSERT INTO Matches (
  match_id,
  host_team,
  guest_team,
  host_goals,
  guest_goals
) 
VALUES
  (4, 20, 30, 1, 0) ;
  
INSERT INTO Matches (
  match_id,
  host_team,
  guest_team,
  host_goals,
  guest_goals
) 
VALUES
  (5, 50, 30, 1, 0) ;

 

 

SQL思路:

一、查询每场比赛各队伍得分:

 # 作为主队的得分统计:
1 SELECT 2 team_id, 3 team_name, 4 IF( 5 host_goals > guest_goals, 6 3, 7 IF(host_goals = guest_goals, 1, 0) 8 ) AS points 9 FROM 10 teams, 11 matches 12 WHERE team_id = host_team;
 #作为客队的得分统计
1 SELECT 2 team_id, 3 team_name, 4 IF( 5 host_goals > guest_goals, 6 0, 7 IF(host_goals = guest_goals, 1, 3) 8 ) AS points 9 FROM 10 teams, 11 matches 12 WHERE team_id = guest_team;

二、将上两张表union all ,然后分组聚合查询,然后发现少了没参赛队伍的积分。因此需要left join 。最终查询语句如下

 1 SELECT 
 2   t.team_id,
 3   t.team_name,
 4   SUM(IFNULL(points,0)) AS num_points
 5 FROM
 6 teams t LEFT JOIN 
 7 (
 8 SELECT 
 9   team_id,
10   team_name,
11   IF(
12     host_goals > guest_goals,
13     3,
14     IF(host_goals = guest_goals, 1, 0)
15   ) AS points 
16 FROM
17   teams,
18   matches 
19 WHERE team_id = host_team 
20 UNION ALL
21 SELECT 
22   team_id,
23   team_name,
24   IF(
25     host_goals > guest_goals,
26     0,
27     IF(host_goals = guest_goals, 1, 3)
28   ) AS points 
29 FROM
30   teams,
31   matches 
32 WHERE team_id = guest_team
33 )temp ON 
34 t.team_id = temp.team_id
35 GROUP BY team_id
36 ORDER BY num_points DESC ,team_id ASC ;

 

标签:1212,Tournament,guest,Football,host,goals,team,id,name
来源: https://www.cnblogs.com/onePunchCoder/p/11619433.html