P1314-聪明的质检员

 1 #include <bits/stdc++.h>
 2 using namespace std;
 3 #define _for(i,a,b) for(int i = (a);i < b;i ++)
 4 #define _rep(i,a,b) for(int i = (a);i > b;i --)
 5 #define INF 0x3f3f3f3f3f3f3f3f
 6 #define pb push_back
 7 #define maxn 2005390
 8 typedef long long ll;
 9 
10 inline ll read()
11 {
12     ll ans = 0;
13     char ch = getchar(), last = ' ';
14     while(!isdigit(ch)) last = ch, ch = getchar();
15     while(isdigit(ch)) ans = (ans << 1) + (ans << 3) + ch - '0', ch = getchar();
16     if(last == '-') ans = -ans;
17     return ans;
18 }
19 inline void write(ll x)
20 {
21     if(x < 0) x = -x, putchar('-');
22     if(x >= 10) write(x / 10);
23     putchar(x % 10 + '0');
24 }
25 ll n,m,S;
26 ll w[maxn],v[maxn];
27 ll L[maxn],R[maxn];
28 ll pren[maxn],preV[maxn];
29 ll rnt = INF;
30 //ll MIN = INF,MAX = 0;
31 bool C(ll d)
32 {
33     ll ans = 0;
34     _for(i,1,n+1)
35         if(w[i]>=d)
36             pren[i] = pren[i-1]+1,preV[i] = preV[i-1]+v[i];
37         else
38             pren[i] = pren[i-1],preV[i] = preV[i-1];
39 
40     _for(i,1,m+1)
41         ans += (pren[R[i]]-pren[L[i]-1])*(preV[R[i]]-preV[L[i]-1]);
42     rnt = min(rnt,llabs(ans-S));
43     if(ans > S)
44         return true;
45     return false;
46 }
47 ll solve()
48 {
49     ll lb = 0,ub = INF;
50     while(lb < ub)
51     {
52         ll mid =  lb+(ub-lb)/2;
53         memset(pren,0,sizeof(pren));
54         memset(preV,0,sizeof(preV));
55         if(C(mid)) lb = mid+1;
56         else ub = mid;
57     }
58     return rnt;
59 }
60 int main()
61 {
62  //    freopen("testdata.in","r+",stdin);
63     n = read(),m = read(),S = read();
64     _for(i,1,n+1)
65     {
66         w[i] = read();
67         v[i] = read();
68     //    MAX = max(MAX,w[i]);
69     //    MIN = min(MIN,w[i]);
70     }
71     _for(i,1,m+1)
72     {
73         L[i] = read();
74         R[i] = read();
75     }
76     write(solve());
77     return 0;
78 }

标签：pren,read,ll,聪明,P1314,质检员,maxn,ans,preV
来源： https://www.cnblogs.com/Asurudo/p/11614956.html