ZJU 1037Gird-land

思路：n和m分别标识横竖的栅栏数目，当两个都为奇数时，那么必有斜边出现，而且在输出时不必考虑浮点数，直接输出小数点后几位即可。

#include<iostream>
#include<cstdio>
using namespace std;
int main(){
    int T;cin>>T;
    while(T--){
        int n,m;
        cin>>n>>m;
        cout<<m*n<<".";
        if(m%2&&n%2)
            cout<<".41"<<endl;
        else
            cout<<"00"<<endl;
    }
    return 0;
}

标签：输出,land,cout,int,浮点数,cin,1037Gird,ZJU,include
来源： https://www.cnblogs.com/sweet-ginger-candy/p/11542816.html