c – 如果输入字母而不是数字,为什么会出现无限循环?
作者:互联网
参见英文答案 > Infinite loop with cin when typing string while a number is expected 4个
我正在编写这个代码作为家庭作业(刚开始C所以请放轻松).我们刚刚开始的同时,今天和今天的循环.该程序运行正常,但如果您在程序要求输入整数时输入一个字母,它会无限循环.到底是怎么回事? (以下代码)
***编辑:为了澄清,循环的部分是:“您输入的数字是负数.请输入正数以继续.”但是用户没有机会输入另一个号码.它只是继续打印这个.
#include <iostream>
using namespace std;
int main ( )
{
//define variables
int num1, num2, total;
char answer1;
do
{
//user enters a number
cout << "\nPlease enter a positive number and press Enter: \n";
cin >> num1;
//check that the given num1 value is positive
while (num1 < 0)
{
cout << "The number you entered is negative.\nPlease enter a positive number to continue.\n";
cin >> num1;
}
cout << endl;
//add the sum of 1 through num1 value
num2 = 1;
total = 0;
while (num1 >= num2)
{
total = total + num2;
num2 ++;
}
//tell the user the sum
cout << "The total of all the integers\nfrom 1 to " << num1 << " is: \n";
cout << total;
//ask if the user wants to try again
cout << "\n\nWould you like to try again with a new number?\nEnter y for yes or n for no.\n";
cin >> answer1;
} while (answer1 == 'y');
cout << endl;
return 0;
}
解决方法:
这就是basic_istream的工作原理.在您的情况下,当cin>> num1输入错误 – 设置failbit并且不清除cin.所以下次它将是相同的错误输入.要正确处理此问题,您可以添加检查输入正确,并在输入错误时清除&忽略cin.例如:
#include<limits>
//user enters a number
cout << "\nPlease enter a positive number and press Enter: \n";
do {
while(!(cin >> num1)) {
cout << "Incorrect input. Please try again.\n";
cin.clear();
cin.ignore(numeric_limits<streamsize>::max(), '\n');
}
if(num1 < 0) cout << "The number you entered is negative. Please enter a positive number to continue.\n";
} while(num1 < 0);
标签:c,infinite-loop 来源: https://codeday.me/bug/20190915/1805489.html