c – 将HBITMAP绘制到分层窗口上.怎么了?
作者:互联网
大家好,祝大家好,
我的最终目标是在屏幕上绘制一个包含alpha的PNG文件 – 这意味着不要进入自己的窗口,而只是桌面上的某个地方.
将PNG加载到HBITMAP中的部分现在可以正常工作(以不同的方式进行测试),但我无法绘制它,包括alpha.
据我所知,最好的方法是使用alyered窗户.所以我花了很多时间来重做几个例子和小教程.
下面的代码编译没有问题,并且没有提示任何消息(这意味着永远不会调用showError(“#”)函数).
然而屏幕上看不到任何东西:/
对不起,它已经很久了…希望有人愿意至少快点看看它.
LRESULT CALLBACK WndProc(HWND hWindow, UINT msg, WPARAM wParam, LPARAM lParam);
int main(HINSTANCE hInstance)
{
WNDCLASSEX WndClass;
char sClassName[] = "mainClass";
WndClass.cbSize = sizeof(WNDCLASSEX);
WndClass.style = NULL;
WndClass.lpfnWndProc = WndProc;//WndProc;
WndClass.cbClsExtra = 0;
WndClass.cbWndExtra = 0;
WndClass.hInstance = hInstance;
WndClass.hIcon = NULL;
WndClass.hCursor = LoadCursor(NULL, IDC_ARROW);
WndClass.hbrBackground = (HBRUSH)(COLOR_WINDOW+1);
WndClass.lpszMenuName = NULL;
WndClass.lpszClassName = sClassName;
WndClass.hIconSm = LoadIcon(NULL, IDI_APPLICATION);
if (RegisterClassEx(&WndClass) == 0) showError("-1");
HWND screen = CreateWindowEx(WS_EX_LAYERED,//WS_EX_LEFT
"mainClass",
"UpdateLayeredWind",
WS_DISABLED | WS_VISIBLE,
200,200,260,260,
NULL /*eventuelly, GM window*/,
NULL,
hInstance,
NULL);
if (screen == NULL) showError("0");
HBITMAP img = LoadImageResource("D://ThreadDraw/ThreadDraw-test/ThreadDraw/test.png");
if (img == NULL) showError("1");
BLENDFUNCTION blend = {0};
blend.AlphaFormat = AC_SRC_ALPHA;
blend.SourceConstantAlpha = 155;
POINT ptPos = {200,300};
SIZE sizeWnd = {260,260};
POINT ptPos2 = {200,300};
ShowWindow(screen, SW_SHOW);
while (1)
{
PAINTSTRUCT ps;
HDC hdc;
BITMAP bitmap;
HDC hdcMem;
HGDIOBJ oldBitmap;
hdc = BeginPaint(screen, &ps);
hdcMem = CreateCompatibleDC(hdc);
oldBitmap = SelectObject(hdcMem, img);
GetObject(img, sizeof(bitmap), &bitmap);
if (SetLayout(hdc,LAYOUT_RTL) == GDI_ERROR)
showError("5");
if (!BitBlt(hdc, 0, 0, 64, 64, hdcMem, 0, 0, SRCCOPY))
showError("4");
if (!UpdateLayeredWindow(screen,hdcMem,&ptPos,&sizeWnd,hdc,&ptPos2,RGB(255,255,255),&blend,ULW_ALPHA))//ULW_OPAQUE))
showError("2");
EndPaint(screen, &ps);
SelectObject(hdcMem, oldBitmap);
DeleteDC(hdcMem);
Sleep(10);
}
return 0;
}
LRESULT CALLBACK WndProc(HWND hwnd, UINT Message, WPARAM wParam, LPARAM lParam)
{
switch(Message)
{
case WM_CLOSE:
DestroyWindow(hwnd);
break;
case WM_DESTROY:
PostQuitMessage(0);
break;
default:
return DefWindowProc(hwnd, Message, wParam, lParam);
}
return 0;
}
顺便说一句,如果我在UpdateLayeredWindow中使用ULW_OPAQUE而不是ULW_ALPHA,那么会出现一个正确大小的黑色窗口,所以认为问题必须是与PAINTSTRUKT或BitBlt函数相关的最小问题.但是我尝试了很多方法而没有任何改变.
希望有人能提供帮助.非常感谢你提前!
解决方法:
这大多是错的.你的代码应该:
>使用CreateWindowEx创建分层窗口.
>使用UpdateLayeredWindow将位图附加到它.
>使用ShowWindow显示窗口. Windows将负责绘制分层窗口,因此您无需处理WM_PAINT或调用BeginPaint.
>输入消息循环.
就是这样.
如果您正在使用Visual Studio,请创建一个新的Win32项目,它将为您创建一个带有消息循环的新项目.
更新
这是一个创建透明分层窗口的示例程序.它需要一个函数来将PNG加载为透明位图.它没有错误检查.
int APIENTRY _tWinMain(HINSTANCE hInstance, HINSTANCE hPrevInstance, LPTSTR lpCmdLine, int nCmdShow)
{
LPCTSTR szWindowClass = _T("TransparentClass");
// Register class
WNDCLASSEX wcex = {0};
wcex.cbSize = sizeof(WNDCLASSEX);
wcex.lpfnWndProc = DefWindowProc;
wcex.hInstance = hInstance;
wcex.lpszClassName = szWindowClass;
RegisterClassEx(&wcex);
HWND hWnd = CreateWindowEx(WS_EX_LAYERED, szWindowClass, 0, WS_OVERLAPPEDWINDOW,
CW_USEDEFAULT, 0, CW_USEDEFAULT, 0, NULL, NULL, hInstance, NULL);
int width;
int height;
HBITMAP hbmp = LoadPng(L"sample.png", &width, &height);
HDC hdcScreen = GetDC(0);
HDC hdc = CreateCompatibleDC(hdcScreen);
ReleaseDC(0, hdcScreen);
HBITMAP hbmpold = (HBITMAP)SelectObject(hdc, hbmp);
POINT dcOffset = {0, 0};
SIZE size = {width, height};
BLENDFUNCTION bf;
bf.BlendOp = AC_SRC_OVER;
bf.BlendFlags = 0;
bf.SourceConstantAlpha = 255;
bf.AlphaFormat = AC_SRC_ALPHA;
UpdateLayeredWindow(hWnd, 0, 0, &size, hdc, &dcOffset, 0, &bf, ULW_ALPHA);
SelectObject(hdc, hbmpold);
DeleteDC(hdc);
DeleteObject(hbmp);
ShowWindow(hWnd, SW_SHOW);
MSG msg;
// Main message loop:
while (GetMessage(&msg, NULL, 0, 0))
{
TranslateMessage(&msg);
DispatchMessage(&msg);
}
return (int)msg.wParam;
}
另一个更新
这里有一些代码用alpha预乘红色,绿色和蓝色值.它假设splash_image指向大小为width * height的32bpp ARGB数据.
LPBYTE bits = (LPBYTE)splash_image;
int size = width * height;
for (int pixel = 0; pixel != size; ++pixel)
{
bits[0] = bits[0] * bits[3] / 255;
bits[1] = bits[1] * bits[3] / 255;
bits[2] = bits[2] * bits[3] / 255;
bits += 4;
}
标签:hbitmap,c,windows,winapi,layered-windows 来源: https://codeday.me/bug/20190901/1785452.html