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求字符串中出现次数最多的子串及其出现次数

作者:互联网

题目描述:

求字符串中出现次数最多的子串的出现次数。
例如字符串abcbcbcabc,出现次数最多的子串是bc,出现次数为4

思路:利用后缀数组:

abcbcbcabc    第0个
bcbcbcabc    第1个
cbcbcabc    第2个
bcbcabc    第3个
cbcabc    第4个
bcabc    第5个
cabc    第6个
abc    第7个
bc    第8个
c    第9个

过程:先从第0个数组取出a,然后和第1个数组的b比较,发现不相等,然后取ab,abc,abcb....这一趟取完后,又从第1个后缀数组开始取,取b,bc,bcb,bcbc...

#include<iostream>
#include<string>
#include<vector>

using namespace std;

pair<int, string> fun(const string &str)
{
    vector<string> substrs;
    int len = str.length();

    string substring;
    int maxcount(0);
    //后缀数组
    cout << "the string is:" << str << endl;
    cout << "the substrings are as follows:" << endl;
    for (int i = 0; i < len; ++i)
    {
        substrs.push_back(str.substr(i));
        cout << substrs[i] << endl;
    }

    cout << "--------------the answer------------" << endl;

    for (int i = 0; i < len; ++i)
    {
        for (int j = 1; j <= len; j++) {
            int count = 1;
            int sublen = j;
            for (int k = i + 1; k < len; k++) {
                
                if (substrs[k].length() < sublen) {
                    break;
                }
                //cout << substrs[i].substr(0, sublen) << endl;
                //cout << substrs[k].substr(0, sublen) << endl;
                string str1 = substrs[i].substr(0, sublen);
                string str2 = substrs[k].substr(0, sublen);
                //cout << "比较结果:" << str1.compare(str2) << endl;
                //cout << "i = " << i << "  sublen = " << j << "  k = " << k << endl;
                if (str1.compare(str2)==0)
                {
                    ++count;
                }
                //cout << "count = " << count << endl;
            }
            if (count > maxcount||(count == maxcount && sublen > substring.length()))
            {
                maxcount = count;
                substring = substrs[i].substr(0, sublen);
            }
        }
    }

    return make_pair(maxcount, substring);

}


int main()
{
    string str = "ababcababcabcab";
    auto res = fun(str);

    cout << "the max count is:" << res.first << endl;
    cout << "the matched substring is:" << res.second << endl;
    return 0;
}

输出:

the string is:ababcababcabcab
the substrings are as follows:
ababcababcabcab
babcababcabcab
abcababcabcab
bcababcabcab
cababcabcab
ababcabcab
babcabcab
abcabcab
bcabcab
cabcab
abcab
bcab
cab
ab
b
--------------the answer------------
the max count is:6
the matched substring is:ab

参考资料:

[1] 求一个字符串中连续出现次数最多的子串 https://blog.csdn.net/qq_22080999/article/details/81143555
[2] 【算法刷题】一个字符串中连续出现次数最多的子串 https://blog.csdn.net/Neo_dot/article/details/80559744

标签:子串,string,substring,次数,str,maxcount,字符串
来源: https://www.cnblogs.com/hellovan/p/11441447.html