1154 Vertex Coloring (25 分)
作者:互联网
A proper vertex coloring is a labeling of the graph's vertices with colors such that no two vertices sharing the same edge have the same color. A coloring using at most k colors is called a (proper) k-coloring.
Now you are supposed to tell if a given coloring is a proper k-coloring.
Input Specification:
Each input file contains one test case. For each case, the first line gives two positive integers N and M (both no more than 1), being the total numbers of vertices and edges, respectively. Then M lines follow, each describes an edge by giving the indices (from 0 to N−1) of the two ends of the edge.
After the graph, a positive integer K (≤ 100) is given, which is the number of colorings you are supposed to check. Then K lines follow, each contains N colors which are represented by non-negative integers in the range of int. The i-th color is the color of the i-th vertex.
Output Specification:
For each coloring, print in a line k-coloring
if it is a proper k
-coloring for some positive k
, or No
if not.
Sample Input:
10 11
8 7
6 8
4 5
8 4
8 1
1 2
1 4
9 8
9 1
1 0
2 4
4
0 1 0 1 4 1 0 1 3 0
0 1 0 1 4 1 0 1 0 0
8 1 0 1 4 1 0 5 3 0
1 2 3 4 5 6 7 8 8 9
Sample Output:
4-coloring
No
6-coloring
No
着色,判断是否有两个连在一起的点用了同一颜色,没有就输出总颜色数量,否则输出No
1 #include <bits/stdc++.h> 2 3 using namespace std; 4 int n, m, k; 5 struct Node{ 6 int u,v; 7 }node[10005]; 8 int val[10005], vis[10005]; 9 10 bool dfs(){ 11 for(int i = 0; i < m; i++){ 12 if(val[node[i].u] == val[node[i].v]) 13 return false; 14 } 15 return true; 16 } 17 18 int main(){ 19 cin >> n >> m; 20 int x,y; 21 for(int i = 0 ; i < m; ++i){ 22 cin >> x >> y; 23 node[i].u = x; 24 node[i].v = y; 25 } 26 cin >> k; 27 while(k--){ 28 map<int,int> mp; 29 int cnt = 0; 30 for(int i = 0; i < n; i++){ 31 cin >> val[i]; 32 if(mp[val[i]] == 0){ 33 mp[val[i]] = 1; 34 cnt++; 35 } 36 } 37 if(dfs()){ 38 cout <<cnt<<"-coloring"<<endl; 39 }else{ 40 cout << "No" << endl; 41 } 42 } 43 return 0; 44 }
标签:node,Coloring,val,int,1154,Vertex,coloring,each,proper 来源: https://www.cnblogs.com/zllwxm123/p/11269346.html