1108. Defanging an IP Address

1108. Defanging an IP Address

题目描述

Example 1:

Input: address = "1.1.1.1"
Output: "1[.]1[.]1[.]1"

Example 2:

Input: address = "255.100.50.0"
Output: "255[.]100[.]50[.]0"

分析：

题目的目的就是将一个字符串里的字符.替换为[.]。

方法1

1. 创建一个空字符ans作为答案；
2. 遍历address，如果字符是.，就在ans后追加[.]，否则就追加该字符；
3. 返回ans；

class Solution {
    public String defangIPaddr(String address) {
        char[] chars = address.toCharArray();
        StringBuilder stringbuilder = new StringBuilder();
        for (char c : chars) {
            if (c == '.') {
                stringbuilder.append("[.]");
            } else {
                stringbuilder.append(c);
            }
        }
        
        return stringbuilder.toString();
    }
}

方法2

使用子串的方法，根据.的位置获取子字符串，并替换.为[.]，再使用字符串连接即可；

class Solution {
    public String defangIPaddr(String address) {
        for (int i = 0; i < address.length(); i++) {
            if (address.charAt(i) == '.') {
                address = address.substring(0, i) + "[.]" + address.substring(i + 1);
                i += 2;
            }
        }
        return address;
    }
}

标签：字符,Defanging,String,IP,address,ans,stringbuilder,字符串,1108
来源： https://www.cnblogs.com/zhuobo/p/11257113.html