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android – 防止用户选择过去的时间 – TimePickerDialog

作者:互联网

重要编辑:我已经做了一些搜索,似乎OnTimeChangedListener不会在Android 5.0(API 21)中触发. Gustavo的答案将适用于API 20或更低版本,以及我测试过的API 22. (Source)

我想阻止用户输入当前时间之前的时间.我使用Date提供的before方法检查有效时间.如何防止对话框在此有效性检查中接受无效时间?

我在初始化所选时间(作为日期)时省略了多余的代码.

final Calendar mcurrentTime = Calendar.getInstance();
final int hour = mcurrentTime.get(Calendar.HOUR_OF_DAY);
final int minute = mcurrentTime.get(Calendar.MINUTE);
final TimePickerDialog mTimePicker;
mTimePicker = new TimePickerDialog(MainActivity.this, new TimePickerDialog.OnTimeSetListener() {
    @Override
    public void onTimeSet(TimePicker timePicker, int selectedHour, int selectedMinute) {

        //PSEUDO: Date selectedDateTime init here

        if (selectedDateTime.before(mcurrentTime.getTime())) {
            // prevent user from selecting time
        }
    }
}, hour, minute, true);//true = 24 hour time
mTimePicker.setTitle("Select Time");
mTimePicker.show(); 

解决方法:

Here原帖.

下面的答案你应该添加TimePickerDialog类.

public class RangeTimePickerDialog extends TimePickerDialog {

private int minHour = -1;
private int minMinute = -1;

private int maxHour = 25;
private int maxMinute = 25;

private int currentHour = 0;
private int currentMinute = 0;

private Calendar calendar = Calendar.getInstance();
private DateFormat dateFormat;


public RangeTimePickerDialog(Context context, OnTimeSetListener callBack, int hourOfDay, int minute, boolean is24HourView) {
    super(context, callBack, hourOfDay, minute, is24HourView);
    currentHour = hourOfDay;
    currentMinute = minute;
    dateFormat = DateFormat.getTimeInstance(DateFormat.SHORT);

    try {
        Class<?> superclass = getClass().getSuperclass();
        Field mTimePickerField = superclass.getDeclaredField("mTimePicker");
        mTimePickerField.setAccessible(true);
        TimePicker mTimePicker = (TimePicker) mTimePickerField.get(this);
        mTimePicker.setOnTimeChangedListener(this);
    } catch (NoSuchFieldException e) {
    } catch (IllegalArgumentException e) {
    } catch (IllegalAccessException e) {
    }
}

public void setMin(int hour, int minute) {
    minHour = hour;
    minMinute = minute;
}

public void setMax(int hour, int minute) {
    maxHour = hour;
    maxMinute = minute;
}

@Override
public void onTimeChanged(TimePicker view, int hourOfDay, int minute) {

    Log.d("DADADADA", "onTimeChanged");

    boolean validTime = true;
    if (hourOfDay < minHour || (hourOfDay == minHour && minute < minMinute)) {
        validTime = false;
    }

    if (hourOfDay > maxHour || (hourOfDay == maxHour && minute > maxMinute)) {
        validTime = false;
    }

    if (validTime) {
        currentHour = hourOfDay;
        currentMinute = minute;
    }

    updateTime(currentHour, currentMinute);
    updateDialogTitle(view, currentHour, currentMinute);
}

private void updateDialogTitle(TimePicker timePicker, int hourOfDay, int minute) {
    calendar.set(Calendar.HOUR_OF_DAY, hourOfDay);
    calendar.set(Calendar.MINUTE, minute);
    String title = dateFormat.format(calendar.getTime());
    setTitle(title);
}
}

之后,将RangeTimePickerDialog替换为TimeTimePickerDialog

public class MainActivity extends Activity {

@Override
protected void onCreate(Bundle savedInstanceState) {
    super.onCreate(savedInstanceState);
    setContentView(R.layout.activity_main);

    final Calendar mcurrentTime = Calendar.getInstance();
    final int hour = mcurrentTime.get(Calendar.HOUR_OF_DAY);
    final int minute = mcurrentTime.get(Calendar.MINUTE);
    final RangeTimePickerDialog mTimePicker;
    mTimePicker = new RangeTimePickerDialog(MainActivity.this, new TimePickerDialog.OnTimeSetListener() {
        @Override
        public void onTimeSet(TimePicker timePicker, int selectedHour, int selectedMinute) {

            Log.d("TAG", "inside OnTimeSetListener");

        }
    }, hour, minute, true);//true = 24 hour time
    mTimePicker.setTitle("Select Time");
    mTimePicker.setMin(hour, minute);
    mTimePicker.show();
}
}

在那之后,检查对话框,时间没有通过限制,我已经使用setMax()或setMin()检查了这一点,并且只设置了一个.

标签:timepicker,android,datetime,date,android-dialog
来源: https://codeday.me/bug/20190724/1527432.html