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Educational Codeforces Round 69 (Rated for Div. 2) A - DIY Wooden Ladder

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Educational Codeforces Round 69 (Rated for Div. 2)

 

A - DIY Wooden Ladder

Let's denote a k-step ladder as the following structure: exactly k+2 wooden planks, of which

Note that neither the base planks, nor the steps planks are required to be equal.

For example, ladders 1 and 3 are correct 2-step ladders and ladder 2 is a correct 1-step ladder. On the first picture the lengths of planks are [3,3] for the base and [1] for the step. On the second picture lengths are [3,3] for the base and [2] for the step. On the third picture lengths are [3,4] for the base and [2,3] for the steps.

 

 

You have n planks. The length of the i-th planks is ai. You don't have a saw, so you can't cut the planks you have. Though you have a hammer and nails, so you can assemble the improvised "ladder" from the planks.

The question is: what is the maximum number k such that you can choose some subset of the given planks and assemble a k-step ladder using them?

Input

The first line contains a single integer T (1≤T≤100) — the number of queries. The queries are independent.

Each query consists of two lines. The first line contains a single integer n (2≤n≤105) — the number of planks you have.

The second line contains n integers a1,a2,…,an (1≤ai≤105) — the lengths of the corresponding planks.

It's guaranteed that the total number of planks from all queries doesn't exceed 105.

Output

Print T integers — one per query. The i-th integer is the maximum number k, such that you can choose some subset of the planks given in the i-th query and assemble a k-step ladder using them.

Print 0 if you can't make even 1-step ladder from the given set of planks.

Example

input

4

4

1 3 1 3

3

3 3 2

5

2 3 3 4 2

3

1 1 2

output

2

1

2

0

Note

Examples for the queries 1−3 are shown at the image in the legend section.

The Russian meme to express the quality of the ladders:

 

 

题意:题目意思就是 定义k阶梯子为两边各一块木板长度至少k+1,中间k块木板至少为1 。

         问 给你n块木板,最多能搭成几阶的梯子。

思路:显然对n块木板排序之后,取最长的两块木板搭旁边的两块梯子为最优解,

  然后就是比较 最长的这两块木板的小的这块长度-1 和 剩余木板数量 的极小值为答案。

 

 1 #include<iostream>
 2 #include<cstdio>
 3 #include<cmath>
 4 #include<cstring>
 5 #include<algorithm>
 6 #include<map>
 7 #include<set>
 8 #include<vector>
 9 #include<queue>
10 using namespace std;
11 #define ll long long 
12 const int mod=1e9+7;
13 const int inf=1e9+7;
14 
15 const int maxn=1e5+5;
16 int num[maxn];
17 
18 int main()
19 {
20     ios::sync_with_stdio(false);cin.tie(0);cout.tie(0);
21     
22     int T;
23     cin>>T;
24     int n;
25     while(T--)
26     {
27         cin>>n;
28         
29         for(int i=0;i<n;i++)
30             cin>>num[i];
31         
32         sort(num,num+n);
33         
34         cout<<min(n-2,num[n-2]-1)<<endl;        
35     }
36     
37     return 0;
38 }

 

标签:Educational,Rated,Wooden,ladder,int,step,base,include,planks
来源: https://www.cnblogs.com/xwl3109377858/p/11239976.html