1089 Insert or Merge (25 分)

According to Wikipedia:

Insertion sort iterates, consuming one input element each repetition, and growing a sorted output list. Each iteration, insertion sort removes one element from the input data, finds the location it belongs within the sorted list, and inserts it there. It repeats until no input elements remain.

Merge sort works as follows: Divide the unsorted list into N sublists, each containing 1 element (a list of 1 element is considered sorted). Then repeatedly merge two adjacent sublists to produce new sorted sublists until there is only 1 sublist remaining.

Now given the initial sequence of integers, together with a sequence which is a result of several iterations of some sorting method, can you tell which sorting method we are using?

Input Specification:

Each input file contains one test case. For each case, the first line gives a positive integer N (≤100). Then in the next line, N integers are given as the initial sequence. The last line contains the partially sorted sequence of the N numbers. It is assumed that the target sequence is always ascending. All the numbers in a line are separated by a space.

Output Specification:

For each test case, print in the first line either "Insertion Sort" or "Merge Sort" to indicate the method used to obtain the partial result. Then run this method for one more iteration and output in the second line the resuling sequence. It is guaranteed that the answer is unique for each test case. All the numbers in a line must be separated by a space, and there must be no extra space at the end of the line.

Sample Input 1:

10
3 1 2 8 7 5 9 4 6 0
1 2 3 7 8 5 9 4 6 0

Sample Output 1:

Insertion Sort
1 2 3 5 7 8 9 4 6 0

Sample Input 2:

10
3 1 2 8 7 5 9 4 0 6
1 3 2 8 5 7 4 9 0 6

Sample Output 2:

Merge Sort
1 2 3 8 4 5 7 9 0 6

  1 #include<bits/stdc++.h>
  2 using namespace std;
  3 
  4 const int maxn=110;
  5 
  6 int a[maxn],b[maxn],c[maxn];
  7 
  8 
  9 int n;
 10 
 11 bool judge(int*a,int *b) 
 12 {
 13     for(int i=0;i<n;i++)
 14     {
 15         if(a[i]!=b[i])
 16             return false;
 17     }
 18     
 19     return true;
 20 }
 21 
 22 
 23 void print(int* a){
 24     for(int i=0;i<n;i++){
 25         
 26         if(i>0)
 27             cout<<" ";
 28         
 29         cout<<a[i];    
 30     }
 31     cout<<endl;
 32 }
 33 
 34 
 35 bool InsertSort(){
 36     
 37     bool flag=false;
 38     
 39     
 40     for(int i=1;i<n;i++){
 41         
 42         int j=i;
 43         
 44         int temp=b[j];
 45     
 46         
 47         if(i!=1&&judge(b,c)){
 48             flag=true;
 49         }
 50         
 51         while(j>0&&temp<b[j-1])//这里错把temp写成b[j]了，要细心
 52         {
 53             b[j]=b[j-1];
 54             j--;    
 55         }
 56         
 57         b[j]=temp;
 58         
 59         
 60         if(flag){
 61             
 62             return true;
 63         }
 64                     
 65     }
 66     
 67     
 68     return false;
 69     
 70 }
 71 
 72 
 73 
 74 void MergeSort(){
 75     
 76     bool flag=false;
 77     
 78     for(int step=2;step/2<=n;step*=2){
 79     
 80         if(step!=2&&judge(b,c)){
 81             flag=true;
 82         }
 83         
 84         for(int i=0;i<n;i+=step){
 85             
 86             sort(b+i,b+min(i+step,n));
 87         }
 88         
 89         if(flag){
 90             cout<<"Merge Sort\n";
 91             print(b);
 92             return;
 93         }
 94         
 95         
 96     }    
 97         
 98 }
 99 
100 
101 
102 
103 int main(){
104     cin>>n;
105     
106     for(int i=0;i<n;i++){
107         cin>>a[i];
108         b[i]=a[i];
109     }
110     
111     for(int i=0;i<n;i++){
112         cin>>c[i];
113     }
114     
115     if(InsertSort()){
116         
117         cout<<"Insertion Sort\n";
118         
119         print(b);
120     }else{
121         
122         for(int i=0;i<n;i++)
123             b[i]=a[i];
124             
125         MergeSort(); 
126     }
127     
128     return 0;    
129 }

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来源： https://www.cnblogs.com/moranzju/p/11157856.html