让动物们叫起来吧！

Problem A: 让动物们叫起来吧！Time Limit: 1 Sec Memory Limit: 128 MB
Submit: 3542 Solved: 2798
[Submit][Status]DescriptionTom家里养了很多动物，比如有鸭子、火鸡和公鸡。它们的叫声都不相同。现在，请编写类Animal、Cock、Turkey和Duck，根据给出的main()函数及样例分析每个类的属性、行为及相互关系，以模仿Tom家的情况。
提示：动物们都有自己的名字。
Input输入有多行。第一行正整数M表示之后有M个测试用例，每个测试用例包括2部分：前一部分是动物的名字，后一部分是动物的类型（用A、B、C分别表示鸭子、火鸡和公鸡）。
Output输出有M行，每个测试用例对应一样。见样例。
Sample Input
3
Baby C
Rubby B
Tobby A
Sample Output
Baby is a cock, and it can crow.
Rubby is a turkey, and it can gobble.
Tobby is a duck, and it can quack.
HINTAppend Codeappend.cc,

#include<istream>
#include<string>
#include <bits/stdc++.h>
using namespace std;
class Animal{
public:
    string name;
    Animal(){}
    Animal(string name_):name(name_){ }
    virtual void sound(){ }
};
class Cock:public Animal
{
public:
    string name;
    Cock(string name_){ name= name_;}
    void sound(){ cout<<name<<" is a cock, and it can crow."<<endl;}
};
class Turkey:public Animal
{
public:
    string name;
    Turkey(string name_):name(name_){ }
    void sound(){ cout<<name<<" is a turkey, and it can gobble."<<endl;}
};
class Duck:public Animal
{
public:
    string name;
    Duck(string name_):name(name_){ }
    void sound(){ cout<<name<<" is a duck, and it can quack."<<endl;}
};
 
int main()
{
    int cases;
    string name;
    char type;
    Animal *animal;
    cin>>cases;
    for (int i = 0; i < cases; i++)
    {
       cin>>name>>type;
       switch(type)
       {
        case 'A':
            animal = new Duck(name);
            break;
        case 'B':
            animal = new Turkey(name);
            break;
        case 'C':
            animal = new Cock(name);
            break;
       }
       animal->sound();
    }
    return 0;
}

标签：起来,name,animal,动物,Animal,include,Cock,string
来源： https://blog.csdn.net/qq_43511633/article/details/94131174