android – WebView无法加载oAuth url

我正在尝试Android Twitter oAuth Connect Tutorial的代码并且它成功运行.我试图将Twitter授权页面更改为在WebView而不是Web浏览器中运行,但WebView似乎无法使用此格式加载url：// twittersample这是返回到我的应用程序的链接.成功授权后,webview应关闭并成功返回我的应用程序.

有一个错误说“oauth：// twittersample？oauth_token = ….的网页可能暂时关闭,或者它可能已永久移动到新的网址”.我该怎么办？

这是我的onCreate中的WebView的片段

WebView myWebView = (WebView)findViewById(R.id.myWebView);

    myWebView.setWebViewClient(new WebViewClient()
    {
    @Override
    public boolean shouldOverrideUrlLoading(WebView webView, String url)
    {
     if (url != null && url.startsWith("oauth://twittersample"))
      //handleTwitterCallback(url);
     {
        System.out.println("TWEET TWEET TWEET");    
        webView.loadUrl(url);
        return true;

        }

     else

     return false;
    }
    }); 

这是我的Twitter java类TWITTER CONNECT CLASS的链接
这是我的表现

<activity android:name="com.test.settings.ShareSettings" android:label="ShareSettings" android:screenOrientation="portrait" android:configChanges="orientation|keyboardHidden">       
        <intent-filter>
            <action android:name="android.intent.action.VIEW" />
            <category android:name="android.intent.category.DEFAULT" />
            <category android:name="android.intent.category.BROWSABLE" />
            <data android:scheme="oauth" android:host="twittersample"/>
        </intent-filter>
    </activity>

附件是在浏览器中成功运行时的logcat

解决方法:

我终于开始工作了.我认为之前它没有用,因为我没有将访问令牌检索到WebView中.

在onCreate下的我的WebView中,我做到了这一点

myWebView = (WebView)findViewById(R.id.myWebView);
    myWebView.setWebViewClient(new WebViewClient()
    {
    @Override
    public boolean shouldOverrideUrlLoading(WebView webView, String url)
    { if (url != null && url.startsWith(TWITTER_CALLBACK_URL))

     { System.out.println("TWEET TWEET TWEET");
        retrieveAccessToken(url); //added this
        webView.setVisibility(View.GONE); //added this
        return true;            
        }

     else

     return false;

    }
    }); 

在我的retrieveAccessToken(url)中我有这个.

private void retrieveAccessToken(final String url)
{
    Uri uri = Uri.parse(url);
    String verifier = uri.getQueryParameter(URL_TWITTER_OAUTH_VERIFIER);

    try {
        // Get the access token
        AccessToken accessToken = twitter.getOAuthAccessToken(requestToken, verifier);

        // Shared Preferences
        Editor e = mSharedPreferences.edit();

        // After getting access token, access token secret
        // store them in application preferences
        e.putString(PREF_KEY_OAUTH_TOKEN, accessToken.getToken());
        e.putString(PREF_KEY_OAUTH_SECRET,accessToken.getTokenSecret());
        // Store login status - true
        e.putBoolean(PREF_KEY_TWITTER_LOGIN, true);
        e.commit(); // save changes

        Log.e("Twitter OAuth Token", "> " + accessToken.getToken());

        TextView twitterConnect = (TextView) findViewById(R.id.twitterConnect);
        String disconnect = "Disconnect";
        twitterConnect.setText(disconnect);                                                     

        // Getting user details from twitter
        // For now i am getting his name only
        long userID = accessToken.getUserId();
        User user = twitter.showUser(userID);
        String username = user.getName();

        txtUpdate.setVisibility(View.VISIBLE);
        btnUpdateStatus.setVisibility(View.VISIBLE);

        // Displaying in xml ui
        //twitterUser.setText(Html.fromHtml("<b>Welcome " + username + "</b>"));
        TextView twitterUser = (TextView) findViewById(R.id.twitterDesc);     
        twitterUser.setText(Html.fromHtml(username));
        Toast.makeText(getApplicationContext(), "LOGGED IN AS " + username, Toast.LENGTH_LONG).show(); 
    } catch (Exception e) {
        // Check log for login errors
        Log.e("Twitter Login Error", "> " + e.getMessage());
    }
}

我让这个工作正是我想要的,并成功登录.
如果我在这里做错了什么,请纠正我.

谢谢@ user1690588和@Nikolay Elenkov,您的时间帮助我.

标签：android,android-webview,android-twitter
来源： https://codeday.me/bug/20190620/1246618.html