leetcode[376] Wiggle Subsequence
作者:互联网
A sequence of numbers is called a wiggle sequence if the differences between successive numbers strictly alternate between positive and negative. The first difference (if one exists) may be either positive or negative. A sequence with fewer than two elements is trivially a wiggle sequence.
For example, [1,7,4,9,2,5]
is a wiggle sequence because the differences (6,-3,5,-7,3)
are alternately positive and negative. In contrast, [1,4,7,2,5]
and [1,7,4,5,5]
are not wiggle sequences, the first because its first two differences are positive and the second because its last difference is zero.
Given a sequence of integers, return the length of the longest subsequence that is a wiggle sequence. A subsequence is obtained by deleting some number of elements (eventually, also zero) from the original sequence, leaving the remaining elements in their original order.
Example 1:
Input: [1,7,4,9,2,5] Output: 6 Explanation: The entire sequence is a wiggle sequence.
Example 2:
Input: [1,17,5,10,13,15,10,5,16,8] Output: 7 Explanation: There are several subsequences that achieve this length. One is [1,17,10,13,10,16,8].
Example 3:
Input: [1,2,3,4,5,6,7,8,9] Output: 2
Follow up:
Can you do it in O(n) time?
题目大意:
找出最长的摆动序列的长度。
解法:
使用两个动态规划数组up和down。
up[i]记录以nums[i]结尾的子序列的长度(该子序列的最后两个元素是递增的)。
down[i]记录以nums[i]结尾的子序列的长度(该子序列的最后两个元素是递减的)。
class Solution { public int wiggleMaxLength(int[] nums) { if (nums.length == 0) return 0; int[] up=new int[nums.length]; int[] down=new int[nums.length]; up[0]=1; down[0]=1; for (int i=1;i<nums.length;i++){ if (nums[i]>nums[i-1]){ up[i]=down[i-1]+1; down[i]=down[i-1]; }else if (nums[i]<nums[i-1]){ down[i]=up[i-1]+1; up[i]=up[i-1]; }else{ down[i]=down[i-1]; up[i]=up[i-1]; } } return Math.max(down[nums.length-1],up[nums.length-1]); } }
标签:wiggle,sequence,int,nums,up,down,Wiggle,Subsequence,leetcode 来源: https://www.cnblogs.com/xiaobaituyun/p/11026751.html