interleaving-string

Given s1, s2, s3, find whether s3 is formed by the interleaving of s1 and s2.

For example,
Given:
s1 =“aabcc”,
s2 =“dbbca”,

When s3 =“aadbbcbcac”, return true.
When s3 =“aadbbbaccc”, return false.

public class Solution {
    public boolean isInterleave(String s1, String s2, String s3) {
        
        if("".equals(s1)){
            return s3.equals(s2);
        }
        if("".equals(s2)){
            return s3.equals(s1);
        }
        if(s3.length()!=s1.length()+s2.length()){
            return false;
        }
        char a1[]=s1.toCharArray();
        char a2[]=s2.toCharArray();
        char a3[]=s3.toCharArray();
        boolean dp[][]=new boolean[s1.length()+1][s2.length()+1];
        //dp[i][j]表示将s1[i-1]和s2[j-1]能否匹配s3
        dp[0][0]=true;
        for(int i=1;i<s1.length()+1;i++){
            dp[i][0]=dp[i-1][0]&(a1[i-1]==a3[i-1+0]);
        }
         for(int i=1;i<s2.length()+1;i++){
            dp[0][i]=dp[0][i-1]&(a2[i-1]==a3[i-1+0]);
        }
        for(int i=1;i<s1.length()+1;i++){
            for(int j=1;j<s2.length()+1;j++){
                 dp[i][j]=(dp[i-1][j]&(a1[i-1]==a3[i-1+j]))
                     ||(dp[i][j-1]&&(a2[j-1]==a3[i-1+j]));
            }
           
        }
        return dp[s1.length()][s2.length()];
    }
}

标签：return,string,s3,s2,interleaving,equals,length,s1
来源： https://blog.csdn.net/qq_30035749/article/details/90574185