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loadrunner逻辑增强

作者:互联网

在脚本上加上一些逻辑,更好判断结果是否成功

Action()
{
    web_reg_save_param(
        "usersession",
        "LB=userSession value=",
        "RB=>",
        LAST
        );

    web_url("webtours", 
        "URL=http://127.0.0.1:1080/webtours/", 
        "Resource=0", 
        "RecContentType=text/html", 
        "Referer=", 
        "Snapshot=t1.inf", 
        "Mode=HTML", 
        LAST);

    lr_think_time(7);

    web_reg_find("Text=jojo",
                 "SaveCount=jojo_count",//保存检查到的次数***
                 LAST);

    web_submit_data("login.pl", 
        "Action=http://127.0.0.1:1080/webtours/login.pl", 
        "Method=POST", 
        "RecContentType=text/html", 
        "Referer=http://127.0.0.1:1080/webtours/nav.pl?in=home", 
        "Snapshot=t2.inf", 
        "Mode=HTML", 
        ITEMDATA, 
        "Name=userSession", "Value={usersession}", ENDITEM, 
        "Name=username", "Value=jojo", ENDITEM, 
        "Name=password", "Value=bean", ENDITEM, 
        "Name=JSFormSubmit", "Value=on", ENDITEM, 
        "Name=login.x", "Value=81", ENDITEM, 
        "Name=login.y", "Value=10", ENDITEM, 
        LAST);

    //增加判断,如果检查到用户名出现的次数大于0,认为登录成功,否则失败***

    if (atoi (lr_eval_string("{jojo_count}")) >0) {
        lr_output_message(" 登录成功");
    }else
        lr_output_message(" 登录失败");



    web_image("SignOff Button", 
        "Alt=SignOff Button", 
        "Snapshot=t3.inf", 
        LAST);

    return 0;
}


-----------------------------------------------------------
重点函数
   web_reg_find("Text=jojo",
                 "SaveCount=jojo_count",//保存检查到的次数***
                 LAST);

  //增加判断,如果检查到用户名出现的次数大于0,认为登录成功,否则失败***

    if (atoi (lr_eval_string("{jojo_count}")) >0) {
        lr_output_message(" 登录成功");
    }else
        lr_output_message(" 登录失败");

常用函数

lr_eval_string

lr_eval_string("{当前想要获取的参数名}");     获取指定的当前参数值

 

strcmp函数

strcmp(字符串1,字符串2);    比较字符串1与字符串2的大小

 

strcpy函数

strcpy(目标字符串,原字符串);       将原字符串拼接到目标字符串后

标签:jojo,web,逻辑,LAST,ENDITEM,loadrunner,增强,Value,lr
来源: https://www.cnblogs.com/hexiaorui123/p/10847757.html