平衡树做题记录

板子就不说了。

P2786 英语1（eng1）- 英语作文

红黑树 map 随便做，用一个 map 存下字符串对应的值，一个字符一个字符读入，然后判断， 如果不是数字并且不是字母，说明空格或者符号，处理答案。

/**
 *	author: TLE_Automation
 *	creater: 2022.9.7
 **/
#include<cmath>
#include<queue>
#include<cstdio>
#include<bitset>
#include<cstring>
#include<iostream>
#include<algorithm>
#define gc getchar 
using namespace std;
typedef long long ll;
const int N = 1e6 + 10;
const int mod = 998244353;
const ll inf = 0x3f3f3f3f3f3f3f3f;
#define debug cout << "i ak ioi" << "\n"
inline void print(int x) {if (x < 0) putchar('-'), x = -x; if(x > 9) print(x / 10); putchar(x % 10 + '0');}
inline char readchar() {static char buf[100000], *p1 = buf, *p2 = buf; return p1 == p2 && (p2 = (p1 = buf) + fread(buf, 1, 100000, stdin), p1 == p2) ? EOF : *p1++;}
inline int read() { int res = 0, f = 0; char ch = gc();for (; !isdigit(ch); ch = gc()) f |= (ch == '-'); for (; isdigit(ch); ch = gc()) res = (res << 1) + (res << 3) + (ch ^ '0'); return f ? -res : res;}

#include <unordered_map>

int n, p, ans;
char ch; string t;
unordered_map <string, int> mp;
signed main() 	
{
	n = read(), p = read();
	for(int i = 1; i <= n; i++) {
		string s; cin >> s; mp[s] = read();
	}
	while((ch = getchar()) && ch != EOF) {
		if(!isdigit(ch) && !isalpha(ch)) ans = (ans + mp[t]) % p, t = "";
		else t += ch;
	}
	printf("%d\n", ans);
	return (0 - 0);
}

标签：ch,记录,int,char,p1,做题,平衡,include,buf
来源： https://www.cnblogs.com/tttttttle/p/16667986.html