递归、二分查找
作者:互联网
#递归函数: 有最大递归深度,默认接近1000,各版本略有差异 count = 0 def F1(n): n += 1 print(n)#1 2 3……996 F1(n) F1(count) #修改递归深度 import sys sys.setrecursionlimit(100) count = 0 def F2(n): n += 1 print(n) # 1 2 3……96 F2(n) F2(count) #二分查找:必须是无重复数字的有序序列 def binary_search(L, numb, start = 0, end = None): if end is None: end = len(L) - 1 m_index = (end - start) // 2 + start if start < end: if numb < L[m_index]: return binary_search(L, numb, start = start, end = m_index) elif numb > L[m_index]: return binary_search(L, numb, start = m_index, end = end) elif numb == L[m_index]: return m_index else: return None else: return None L1 = [1, 3, 5, 6, 7, 8, 11, 23, 44, 46, 53] print(binary_search(L1, 7))#4 #
标签:二分,index,end,递归,binary,start,查找,numb,return 来源: https://www.cnblogs.com/ggsdddup/p/16659543.html