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解决线程安全问题

作者:互联网


方式一:同步代码块


synchronized (同步监视器){
//需要被同步的代码
}
说明:
操作共享数据的代码,即为需要被同步的代码
共享数据:多个线程共同操作的变量
同步监视器:俗称,锁。任何一个类的对象都可以充当锁。(要求:多个线程必须要共用同一把锁)


public class Window implements Runnable {
    private int ticket = 100;
    private Object obj = new Object();

    @Override
    public void run() {
        while (true) {
            synchronized (obj) { //可以用this,此时的this:唯一的Window的对象
                if (ticket > 0) {
                    try {
                        Thread.sleep(100);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    System.out.println(Thread.currentThread().getName() + "***" + ticket);
                    ticket--;
                } else {
                    break;
                }
            }
        }
    }
}

class WindowTest {
    public static void main(String[] args) {
        Window w = new Window();
        Thread t1 = new Thread(w);//3个线程公用1个w对象
        Thread t2 = new Thread(w);
        Thread t3 = new Thread(w);

        t1.setName("线程1");
        t2.setName("线程2");
        t3.setName("线程3");

        t1.start();
        t2.start();
        t3.start();
    }
}

 

 

 

public class ThreadTest {

    public static void main(String[] args) {
        Window1 t1 = new Window1();
        Window1 t2 = new Window1();
        Window1 t3 = new Window1();
        t1.setName("线程1");
        t2.setName("线程2");
        t3.setName("线程3");

        t1.start();
        t2.start();
        t3.start();
    }
}

class Window1 extends Thread{
    private static int ticket = 100;
    private static Object obj = new Object();

    @Override
    public void run() {
        while (true) {
            synchronized (obj) { //可以用Window1.class,类也是对象,在内存中只加载一次
                if (ticket > 0) {
                    try {
                        Thread.sleep(100);
                    } catch (InterruptedException e) {
                        e.printStackTrace();
                    }
                    System.out.println(Thread.currentThread().getName() + "***" + ticket);
                    ticket--;
                } else {
                    break;
                }
            }
        }
    }
}

  

  





标签:Thread,start,Window1,安全,线程,解决,new,ticket
来源: https://www.cnblogs.com/ixtao/p/16581534.html