相似记录中查找出最新的一条记录

SELECT a*
        FROM amj_aged_nursing_cost a
WHERE NOT EXISTS(
            SELECT *
            FROM amj_aged_nursing_cost b
            WHERE b.aged_card_num = a.aged_card_num
            AND b.create_time > a.create_time
            AND b.id > a.id
            )
ORDER BY a.aged_card_num

标签：amj,cost,nursing,记录,查找,num,相似,aged,card
来源： https://www.cnblogs.com/ikunn/p/16575625.html