[AcWing 178] 第K短路
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A* 算法
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#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
typedef pair<int,int> PII;
typedef pair<int,PII> PIPII;
const int N = 1e6 + 10;
int n, m, S, T, K;
int h[N], rh[N], e[N], ne[N], w[N], idx;
int d[N], cnt[N];
bool st[N];
void add(int h[], int a, int b, int c)
{
e[idx] = b;
w[idx] = c;
ne[idx] = h[a];
h[a] = idx ++;
}
void dijkstra()
{
priority_queue<PII, vector<PII>, greater<PII>> heap;
heap.push({0, T});
memset(d, 0x3f, sizeof d);
d[T] = 0;
while (heap.size()) {
auto t = heap.top();
heap.pop();
int v = t.second;
if (st[v])
continue;
st[v] = true;
for (int i = rh[v]; i != -1; i = ne[i]) {
int j = e[i];
if (d[j] > d[v] + w[i]) {
d[j] = d[v] + w[i];
heap.push({d[j], j});
}
}
}
}
int astar()
{
priority_queue<PIPII, vector<PIPII>, greater<PIPII>> heap;
heap.push({d[S], {0, S}});
while (heap.size()) {
auto t = heap.top();
heap.pop();
int v = t.second.second, dist = t.second.first;
cnt[v] ++;
if (cnt[T] == K)
return dist;
for (int i = h[v]; i != -1; i = ne[i]) {
int j = e[i];
if (cnt[j] < K)
heap.push({dist + w[i] + d[j], {dist + w[i], j}});
}
}
return -1;
}
void solve()
{
cin >> n >> m;
memset(h, -1, sizeof h);
memset(rh, -1, sizeof rh);
for (int i = 0; i < m; i ++) {
int a, b, c;
cin >> a >> b >> c;
add(h, a, b, c);
add(rh, b, a, c);
}
cin >> S >> T >> K;
if (S == T)
K ++;
dijkstra();
cout << astar() << endl;
}
signed main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
solve();
return 0;
}
- 估价函数
每个点到终点的最短距离
标签:dist,idx,int,短路,second,heap,178,rh,AcWing 来源: https://www.cnblogs.com/wKingYu/p/16557659.html