AcWing 178. 第K短路(搜索)
作者:互联网
题目描述
题目思路
- A*算法:终点第一次从终点弹出时,一定是最小值
- 估价函数:从当前点到终点的最短距离,估计距离<=真实距离(在终点跑一遍dijkstra算法即可)
- 终点弹第几次就是第几短路
题目代码
#include <iostream>
#include <cstring>
#include <algorithm>
#include <queue>
#define x first
#define y second
using namespace std;
typedef pair<int, int> PII;
typedef pair<int, PII> PIII;
const int N = 1010, M = 200010;
int n, m, S, T, K;
int h[N], rh[N], e[M], w[M], ne[M], idx;
int dist[N], cnt[N]; // dist记录终点到每个点的最短距离 cnt记录每个点弹出多少次
bool st[N];
void add(int h[], int a, int b, int c)
{
e[idx] = b, w[idx] = c, ne[idx] = h[a], h[a] = idx ++ ;
}
void dijkstra()
{
priority_queue<PII, vector<PII>, greater<PII>> heap;
heap.push({0, T}); // 距离 编号
memset(dist, 0x3f, sizeof dist);
dist[T] = 0;
while (heap.size())
{
auto t = heap.top();
heap.pop();
int ver = t.y;
if (st[ver]) continue;
st[ver] = true;
for (int i = rh[ver]; ~i; i = ne[i])
{
int j = e[i];
if (dist[j] > dist[ver] + w[i])
{
dist[j] = dist[ver] + w[i];
heap.push({dist[j], j});
}
}
}
}
int astar()
{
priority_queue<PIII, vector<PIII>, greater<PIII>> heap;
heap.push({dist[S], {0, S}}); // 估计距离 真实距离 编号
while(heap.size())
{
auto t = heap.top();
heap.pop();
int ver = t.y.y, distance = t.y.x;
cnt[ver] ++;
if(cnt[T] == K) return distance;
for(int i = h[ver]; ~i; i = ne[i])
{
int j = e[i];
if(cnt[j] < K)
heap.push({distance + w[i] + dist[j], {distance + w[i], j}});
}
}
return -1;
}
int main()
{
scanf("%d%d", &n, &m);
memset(h, -1, sizeof h);
memset(rh, -1, sizeof rh);
for(int i = 0; i < m; i ++ )
{
int a, b, c;
scanf("%d%d%d", &a, &b, &c);
add(h, a, b, c);
add(rh, b, a, c);
}
scanf("%d%d%d", &S, &T, &K);
if(S == T) K ++ ;
dijkstra();
printf("%d\n", astar());
return 0;
}
标签:dist,idx,int,短路,d%,heap,178,ver,AcWing 来源: https://www.cnblogs.com/esico/p/16487999.html