[AcWing 1250] 格子游戏
作者:互联网
点击查看代码
#include<bits/stdc++.h>
using namespace std;
typedef long long LL;
const int N = 1e5 + 10;
int n, m;
int p[N];
int find(int x)
{
if (p[x] != x)
p[x] = find(p[x]);
return p[x];
}
void solve()
{
cin >> n >> m;
for (int i = 1; i <= n * n; i ++)
p[i] = i;
int res = 0;
for (int i = 1; i <= m; i ++) {
int x, y;
char c;
cin >> x >> y >> c;
if (res)
continue;
int a = (x - 1) * n + y;
int b = 0;
if (c == 'D')
b = a + n;
else
b = a + 1;
if (find(a) == find(b))
res = i;
p[find(a)] = find(b);
}
if (!res)
cout << "draw" << endl;
else
cout << res << endl;
}
int main()
{
ios::sync_with_stdio(false);
cin.tie(nullptr);
cout.tie(nullptr);
solve();
return 0;
}
- 每次判断两个点是否属于同一个集合,如果在同一个集合,则连线之后会形成圈,否则把两个点属于的集合合并
标签:同一个,格子,int,res,long,1250,集合,find,AcWing 来源: https://www.cnblogs.com/wKingYu/p/16483650.html