问题

如题所示

答案

相关源码：

export function getTimeInterval(startDate, endDate = Date.now()) {
  if (arguments.length === 0) {
    return null
  }
  let startTime;
  let endTime;
  if (typeof startDate === 'object') {
    startTime = startDate.getTime();
  } else {
    startTime = startDate;
  }
  if (typeof endDate === 'object') {
    endTime = endDate.getTime();
  } else {
    endTime = endDate;
  }
  let dateInterval =  endTime - startTime;
  // //计算出相差天数
  let days = Math.floor(dateInterval / (24 * 60 * 60 * 1000));
  //计算小时数
  let hourLevel = dateInterval % (24 * 60 * 60 * 1000);
  let hours = Math.floor(hourLevel / (60 * 60 * 1000))
  //计算分钟数
  let minutesLevel = hourLevel % (60 * 60 * 1000);
  let minutes = Math.floor(minutesLevel / (60 * 1000));
  //计算秒数
  let seconds = Math.round((minutesLevel % (60 * 1000)) / 1000);
  return `${days} 天 ${hours} 时 ${minutes} 分 ${seconds} 秒`;
}

math.floor()函数

综上所述，math.floor()这个方法作用是向下取整，就是取参数小的最大整数。

标签：startDate,查漏,floor,60,let,Math,1000
来源： https://www.cnblogs.com/Huang-zihan/p/16460115.html