LeetCode287 寻找重复数（快慢指针寻找环入口）

LeetCode287 寻找重复数

快慢指针寻找环入口

关于判定有环之后如果寻找环入口可参考 参考

class Solution:
    def findDuplicate(self, nums: List[int]) -> int:
        
        slow, fast = nums[0], nums[nums[0]]

        while slow != fast:
            slow = nums[slow]
            fast = nums[nums[fast]]

        slow = 0
        while slow != fast:
            slow = nums[slow]
            fast = nums[fast]
        
        return slow

标签：LeetCode287,slow,nums,int,寻找,fast,入口,指针
来源： https://www.cnblogs.com/solvit/p/16436177.html