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反转链表

作者:互联网

来源:力扣(LeetCode)
链接:https://leetcode.cn/problems/reverse-linked-list

给你单链表的头节点 head ,请你反转链表,并返回反转后的链表。

点击查看代码
    public ListNode reverseList(ListNode head) {
        if(head == null){
            return head;
        }
        ListNode prev = null;
        ListNode curr = head;
        while(curr != null){
            ListNode tmp = curr.next;
            curr.next = prev;
            prev = curr;
            curr = tmp;
        }
        return prev;
    }

示例 1:

输入:head = [1,2,3,4,5]
输出:[5,4,3,2,1]
示例 2:

输入:head = [1,2]
输出:[2,1]
示例 3:

输入:head = []
输出:[]

标签:head,ListNode,示例,反转,链表,curr,prev
来源: https://www.cnblogs.com/xy7112/p/16412741.html