判断字符串是否有重复字条

strs = 'Goaod'

hashTable = dict()

listStrs = list(strs)

i = 0

while i < len(strs):

    if listStrs[i] in hashTable:

        print("有重复字符")

        break

    else:

        hashTable[listStrs[i]] = None

        i += 1

        if i >= len(strs):

            print("没用重复字符")

            break


ee = 'aa111(((bbhhhhhh%jjjjjj%(ccc((vvvv22'

cc='11222333'

def max_letter_count(n):

    list4 = []

    list1 = []

    list2 = []

    for i in n:

        list3 = []

        count_max = n.count(i)

        list3.append(i)

        list3.append(count_max)

        list1.append(list3)

        list2.append(count_max)

        num=max(list2)

        for i in range(len(list2)):

            if list2[i] == num:

                list4.append(list1[i][0])

    #return list(set(list4)),'字符出现最大次数为:%d' % num
    if num>=3:
        return True
    else:
        return False

print(max_letter_count(ee))

标签：count,字条,重复,max,list3,list2,num,字符串,append
来源： https://www.cnblogs.com/xkdn/p/16403882.html