实验五
作者：互联网
任务一：
task1-1
#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M];
char author[M];
}Book;
int main()
{
Book x[N]={{"一九八四","乔治.奥威尔"},
{"美丽新世界","赫胥黎"},
{"昨日的世界","斯蒂芬.茨威格"},
{"万历十五年","黄仁雨"},
{"一只特立独行的猪","王小波"},
};
int i;
FILE *fp;
fp=fopen("datal.txt","w");
if(fp==NULL)
{
printf("fail to open file\n");
return 1;
}
for(i=0;i<N;++i)
{
fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author);
printf("%-20s %-20s\n", x[i].name, x[i].author);
}
fclose(fp);
return 0;
}
task1-2
#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M];// 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N];
int i;
FILE *fp;
// 以读的方式打开文本文件data1.txt
fp = fopen("data1.txt", "r");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 从fp指向的文件data1.txt中读取信息到结构体数组x
// 同时，把x的内容输出到屏幕上
for(i=0; i<N; ++i)
{
fscanf(fp,"%s %s\n", x[i].name, x[i].author);
printf("%-20s %-20s\n", x[i].name, x[i].author);
}
fclose(fp);
return 0;
}
是数组首地址，不用加地址符
任务二：
task2-1
#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M]; // 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N] = {
{"一九八四", "乔治.奥威尔"},
{"美丽新世界", "赫胥黎"},
{"昨日的世界", "斯蒂芬.茨威格"},
{"万历十五年", "黄仁宇"},
{"一只特立独行的猪", "王小波"}
};
int i;
FILE *fp;
// 以写的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "wb");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 将结构体数组x中的图书信息写以数据块方式写入文件
// 把从地址x处开始sizeof(Book)×N个字节大小的数据块写入fp指向的文件
fwrite(x, sizeof(Book), N, fp);
fclose(fp);
return 0;
}
是，是
task2-1
#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M]; // 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N];
int i;
FILE *fp;
// 以读的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "rb");
// 如果打开文件失败，输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 从fp指向的文件中读取数据块到x对应的地址单元
// 数据块大小为sizeof(Book)×N
fread(x, sizeof(Book), N, fp);
// 在屏幕上输出结构体数组x中保存的数据
for(i=0; i<N; ++i)
printf("%-20s%-20s\n", x[i].name, x[i].author);
fclose(fp);
return 0;
}
任务三：
#include <stdio.h>
int main()
{
int s=0;
FILE *fin, *fout;
char ch;
fin = fopen("data3_1.txt", "r");
if(fin == NULL)
{
printf("fail to open data3_1.txt\n");
return 1;
}
fout = fopen("data3_2.txt", "w");
if(fout == NULL)
{
printf("fail to open data3_2.txt\n");
return 1;
}
while( !feof(fin) )
{
ch = fgetc(fin);
if(ch!=('\0'&&'NULL'))
s=s+1;
}
printf("data3_1.txt中共包含字符数：%d",s);
fclose(fin);
fclose(fout);
return 0;
}
任务五：
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define N 10
typedef struct
{
long int id;
char name[20];
float objective;
float subjective;
float sum;
char level[10];
}stu;
void input(stu s[], int n);
void output(stu s[], int n);
void process(stu s[], int n);
int main()
{
stu st[N];
printf("从文件读入%d个考生信息：准考证号，姓名，客观题得分，操作题得分\n", N);
input(st, N);
printf("\n对考生信息进行处理：计算总分，确定等级\n");
process(st, N);
printf("\n打印考生完整信息，并保存到文件中");
output(st, N);
return 0;
}
void input(stu s[], int n)
{
int i;
FILE* fin;
fin = fopen("examinee.txt", "r");
if (fin == NULL)
{
printf("-----");
exit(0);
}
while (!feof(fin))
{
for (i = 0; i < N; i++)
fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective);
}
fclose(fin);
}
void output(stu s[], int n)
{
FILE* fout;
int i;
printf("\n");
printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
for (i = 0; i < N; i++)
printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t%s\n", &s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
fout = fopen("result.txt", "w");
if (!fout)
{
printf("-------");
exit(0);
}
fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
for (i = 0; i < n; i++)
fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
fclose(fout);
}
void process(stu s[], int n)
{
int i = 0;
int j = 0;
stu t;
for (; i < n; i++)
s[i].sum = s[i].objective + s[i].subjective;
for (i=0; i < n-1; i++)
for(j=0;j<n-1-i;j++)
if (s[j].sum < s[j + 1].sum)
{
t = s[j];
s[j] = s[j + 1];
s[j + 1] = t;
}
for (i = 0; i < n; i++)
{
if (i <= n * 0.1-1)
strcpy(s[i].level, "优");
else if (i > n * 0.1-1&&i<=n*0.5-1)
strcpy(s[i].level, "合格");
else
strcpy(s[i].level, "不合格");
}
}
任务六：
#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define N 80
typedef struct
{
long int id;
char name[20];
char grade[100];
}stu;
void input(stu s[], int n);
void output(stu s[], int n);
int main()
{
stu st[N];
printf("从文件读入%d个考生信息：学号，姓名，班级\n", N);
input(st, N);
printf("\n打印考生完整信息，并保存到文件中");
output(st, N);
return 0;
}
void input(stu s[], int n)
{
int i;
FILE* fin;
fin = fopen("list.txt", "r");
if (fin == NULL)
{
printf("-----");
exit(0);
}
while (!feof(fin))
{
for (i = 0; i < n; i++)
fscanf(fin, "%ld %s %s", &s[i].id, s[i].name, s[i].grade);
}
fclose(fin);
}
void output(stu s[], int n)
{
FILE* fout;
int i,a;
fout = fopen("list2.txt", "w");
if (!fout)
{
printf("-------");
exit(0);
}
printf("\n");
printf("准考证号\t姓名\t班级\n");
fprintf(fout, "准考证号\t\t姓名\t班级\n");
srand(time(0));
for (i = 0; i < 5; i++)
{
a = rand() % 80;
printf("%ld\t%s\t%s\n", s[a].id, s[a].name, s[a].grade);
fprintf(fout, "%ld\t%s\t%s\n", s[a].id, s[a].name, s[a].grade);
}
fclose(fout);
}
标签：fp,int,stu,实验,fout,printf,fin 来源： https://www.cnblogs.com/u2807875/p/16351369.html