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实验五

作者:互联网

任务一:

task1-1

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
    char name[M];
    char author[M];
 }Book;
 int main()
 {
     Book x[N]={{"一九八四","乔治.奥威尔"},
               {"美丽新世界","赫胥黎"},
               {"昨日的世界","斯蒂芬.茨威格"}, 
               {"万历十五年","黄仁雨"},
               {"一只特立独行的猪","王小波"},
     };
     int i;
     FILE *fp;
     fp=fopen("datal.txt","w");
     if(fp==NULL)
     {
         printf("fail to open file\n");
         return 1;
     }
     for(i=0;i<N;++i)
     {
      fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author);
      printf("%-20s %-20s\n", x[i].name, x[i].author);
     }
     fclose(fp);
     return 0;
  } 

 

 task1-2

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M];// 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N];
int i;
FILE *fp;
// 以读的方式打开文本文件data1.txt
fp = fopen("data1.txt", "r");
// 如果打开文件失败,输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 从fp指向的文件data1.txt中读取信息到结构体数组x
// 同时,把x的内容输出到屏幕上
for(i=0; i<N; ++i)
{
fscanf(fp,"%s %s\n", x[i].name, x[i].author);
printf("%-20s %-20s\n", x[i].name, x[i].author);
}
fclose(fp);
return 0;
}

 

是数组首地址,不用加地址符

 任务二:

task2-1

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M]; // 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N] = { 
 {"一九八四", "乔治.奥威尔"},
 {"美丽新世界", "赫胥黎"},
{"昨日的世界", "斯蒂芬.茨威格"},
{"万历十五年", "黄仁宇"},
{"一只特立独行的猪", "王小波"}
};
int i;
FILE *fp;
// 以写的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "wb");
// 如果打开文件失败,输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 将结构体数组x中的图书信息写以数据块方式写入文件
// 把从地址x处开始sizeof(Book)×N个字节大小的数据块写入fp指向的文件
fwrite(x, sizeof(Book), N, fp);
fclose(fp);
return 0;
}

是,是

task2-1

#include <stdio.h>
#define N 5
#define M 80
typedef struct
{
char name[M]; // 书名
char author[M]; // 作者
}Book;
int main()
{
Book x[N];
int i;
FILE *fp;
// 以读的方式打开二进制文件data2.dat
fp = fopen("data2.dat", "rb");
// 如果打开文件失败,输出提示信息并返回
if(fp == NULL)
{
printf("fail to open file\n");
return 1;
}
// 从fp指向的文件中读取数据块到x对应的地址单元
// 数据块大小为sizeof(Book)×N
fread(x, sizeof(Book), N, fp);
// 在屏幕上输出结构体数组x中保存的数据
for(i=0; i<N; ++i)
printf("%-20s%-20s\n", x[i].name, x[i].author);
fclose(fp);
return 0;
}

任务三:

 

#include <stdio.h>
int main()
{
    int s=0; 
FILE *fin, *fout;
char ch;
fin = fopen("data3_1.txt", "r");
if(fin == NULL)
{
printf("fail to open data3_1.txt\n");
return 1;
}
fout = fopen("data3_2.txt", "w");
if(fout == NULL)
{
printf("fail to open data3_2.txt\n");
return 1;
}
while( !feof(fin) )
{
ch = fgetc(fin);
if(ch!=('\0'&&'NULL'))
s=s+1;
}
printf("data3_1.txt中共包含字符数:%d",s);
fclose(fin);
fclose(fout);
return 0;
}

任务五:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define N 10
typedef struct
{
    long int id;
    char name[20];
    float objective;
    float subjective;
    float sum;
    char level[10];
}stu;
void input(stu s[], int n);
void output(stu s[], int n);
void process(stu s[], int n);
int main()
{
    stu st[N];
    printf("从文件读入%d个考生信息:准考证号,姓名,客观题得分,操作题得分\n", N);
    input(st, N);
    printf("\n对考生信息进行处理:计算总分,确定等级\n");
    process(st, N);
    printf("\n打印考生完整信息,并保存到文件中");
    output(st, N);
    return 0;
}
void input(stu s[], int n)
{
    int i;
    FILE* fin;
    fin = fopen("examinee.txt", "r");
    if (fin == NULL)
    {
        printf("-----");
        exit(0);
    }
    while (!feof(fin))
    {
        for (i = 0; i < N; i++)
            fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name, &s[i].objective, &s[i].subjective);
    }
    fclose(fin);
}
void output(stu s[], int n)
{
    FILE* fout;
    int i;
    printf("\n");
    printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
    for (i = 0; i < N; i++)
        printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t%s\n", &s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
    fout = fopen("result.txt", "w");
    if (!fout)
    {
        printf("-------");
        exit(0);
    }
    fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n");
    for (i = 0; i < n; i++) 
        fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id, s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level);
    fclose(fout);
}
void process(stu s[], int n)
{
    int i = 0;
    int j = 0;
    stu t;
    for (; i < n; i++)
        s[i].sum = s[i].objective + s[i].subjective;
    for (i=0; i < n-1; i++)
        for(j=0;j<n-1-i;j++)
            if (s[j].sum < s[j + 1].sum)
            {
                t = s[j];
                s[j] = s[j + 1];
                s[j + 1] = t;
            }
    for (i = 0; i < n; i++)
    {
        if (i <= n * 0.1-1)
            strcpy(s[i].level, "优");
        else if (i > n * 0.1-1&&i<=n*0.5-1)
            strcpy(s[i].level, "合格");
        else
            strcpy(s[i].level, "不合格");
    }
}

 

 任务六:

#include<stdio.h>
#include<string.h>
#include<stdlib.h>
#define N 80
typedef struct
{
    long int id;
    char name[20];
    char grade[100];
}stu;
void input(stu s[], int n);
void output(stu s[], int n);
int main()
{
    stu st[N];
    printf("从文件读入%d个考生信息:学号,姓名,班级\n", N);
    input(st, N);
    printf("\n打印考生完整信息,并保存到文件中");
    output(st, N);
    return 0;
}
void input(stu s[], int n)
{
    int i;
    FILE* fin;
    fin = fopen("list.txt", "r");
    if (fin == NULL)
    {
        printf("-----");
        exit(0);
    }
    while (!feof(fin))
    {
        for (i = 0; i < n; i++)
            fscanf(fin, "%ld %s %s", &s[i].id, s[i].name, s[i].grade);
    }
    fclose(fin);
}
void output(stu s[], int n)
{
    FILE* fout;
    int i,a;
    fout = fopen("list2.txt", "w");
    if (!fout)
    {
        printf("-------");
        exit(0);
    }
    printf("\n");
    printf("准考证号\t姓名\t班级\n");
    fprintf(fout, "准考证号\t\t姓名\t班级\n");
    srand(time(0));
    for (i = 0; i < 5; i++)
    {
        a = rand() % 80;
        printf("%ld\t%s\t%s\n", s[a].id, s[a].name, s[a].grade);
        fprintf(fout, "%ld\t%s\t%s\n", s[a].id, s[a].name, s[a].grade);
    }
    fclose(fout);
}

 

标签:fp,int,stu,实验,fout,printf,fin
来源: https://www.cnblogs.com/u2807875/p/16351369.html