实验五
作者:互联网
1.实验任务1:文本文件数据格式化读写
task1_1.c
#include<stdio.h> #define N 5 #define M 80 typedef struct { char name[M]; //书名 char author[M]; //作者 } Book; int main() { Book x[N]={ { "一九八四", "乔治.奥威尔"}, {"美丽新世界", "赫胥黎"}, {"昨日的世界", "斯蒂芬.茨威格"}, {"万历十五年", "黄仁宇"}, {"一只特立独行的猪", "王小波"} }; int i; FILE *fp; // 以写的方式打开文本文件data1.txt fp = fopen("data1.txt", "w"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 将结构体数组x中的图书信息写到fp指向的文件data1.txt // 同时也输出到屏幕上 for(i=0; i<N; ++i) { fprintf(fp, "%-20s %-20s\n", x[i].name, x[i].author); printf("%-20s %-20s\n", x[i].name, x[i].author); } fclose(fp); return 0; }
task1.2
#include <stdio.h> #define N 5 #define M 80 typedef struct { char name[M]; // 书名 char author[M]; // 作者 }Book; int main() { Book x[N]; int i; FILE *fp; // 以读的方式打开文本文件data1.txt fp = fopen("data1.txt", "r"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 从fp指向的文件data1.txt中读取信息到结构体数组x // 同时,把x的内容输出到屏幕上 for(i=0; i<N; ++i) { fscanf(fp, "%s %s\n", x[i].name, x[i].author); printf("%-20s %-20s\n", x[i].name, x[i].author); } fclose(fp); return 0; }
task2.1
#include <stdio.h> #define N 5 #define M 80 typedef struct { char name[M]; // 书名 char author[M]; // 作者 }Book; int main() { Book x[N] = { {"一九八四", "乔治.奥威尔"}, {"美丽新世界", "赫胥黎"}, {"昨日的世界", "斯蒂芬.茨威格"}, {"万历十五年", "黄仁宇"}, {"一只特立独行的猪", "王小波"} }; int i; FILE *fp; // 以写的方式打开二进制文件data2.dat fp = fopen("data2.dat", "wb"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 将结构体数组x中的图书信息写以数据块方式写入文件 // 把从地址x处开始sizeof(Book)×N个字节大小的数据块写入fp指向的文件 fwrite(x, sizeof(Book), N, fp); fclose(fp); return 0; }
task2.2
#include <stdio.h> #define N 5 #define M 80 typedef struct { char name[M]; // 书名 char author[M]; // 作者 }Book; int main() { Book x[N]; int i; FILE *fp; // 以读的方式打开二进制文件data2.dat fp = fopen("data2.dat", "rb"); // 如果打开文件失败,输出提示信息并返回 if(fp == NULL) { printf("fail to open file\n"); return 1; } // 从fp指向的文件中读取数据块到x对应的地址单元 // 数据块大小为sizeof(Book)×N fread(x, sizeof(Book), N, fp); // 在屏幕上输出结构体数组x中保存的数据 for(i=0; i<N; ++i) printf("%-20s%-20s\n", x[i].name, x[i].author); fclose(fp); return 0; }
task3.1
#include <stdio.h> int main() { FILE *fin, *fout; char ch; // 以只读、文本方式打开文件data3_1.txt fin = fopen("data3_1.txt", "r"); // 如果打开失败,输出提示信息并返回 if(fin == NULL) { printf("fail to open data3_1.txt\n"); return 1; } // 以写、文本方式打开文件data3_2.txt fout = fopen("data3_2.txt", "w"); // 如果打开失败,输出提示信息并返回 if(fout == NULL) { printf("fail to open data3_2.txt\n"); return 1; } // 当fin指向的文件data1_txt没有结束时 while( !feof(fin) ) { // 从fin指向的文件data1_txt读取单个字符 ch = fgetc(fin); // 如果ch是小写字母,转换成大写 if(ch >= 'a' && ch <= 'z') ch -= 32; // 将字符变量ch中的字符写入fout指向的文件data3_2.txt fputc(ch, fout); } fclose(fin); fclose(fout); return 0; }
task3.2
#include <stdio.h> int main() { FILE *fin; char ch; int count=0; if((fin=fopen("data3_1.txt","r"))==NULL) { printf("fail to open data3_1.txt"); return 1; } while(!feof(fin)) { ch=fgetc(fin); if(ch!=' '&&ch!='\n'&&ch!='\t'&&ch!=EOF) { count++; } } printf("data3_1.txt中共包含字符数=%d",count); fclose(fin); return 0; }
task4
#include <stdio.h> #define N 5 typedef struct { long no; char name[20]; int score; } STU; int findMinlist(STU s[], int n, STU t[]); int main() { STU stu[N], minlist[N]; int count, i; FILE *fin, *fout; fin = fopen("data4_1.txt", "r"); if(fin == NULL) { printf("fail to open file\n"); return 1; } for(i=0; i<N; ++i) { fscanf(fin, "%ld %s %d", &stu[i].no, stu[i].name, &stu[i].score); printf("%ld %s %d\n", stu[i].no, stu[i].name, stu[i].score); } fclose(fin); count = findMinlist(stu, N, minlist); printf("\n一共有%d个最低分,信息如下: \n", count); for(i=0; i<count; ++i) printf("%ld %s %d\n", minlist[i].no, minlist[i].name,minlist[i].score); fout = fopen("data4_2.txt", "w"); if(fout == NULL) { printf("fail to open file\n"); return 1; } for(i=0; i<count; ++i) fprintf(fout, "%ld %s %d\n", minlist[i].no, minlist[i].name,minlist[i].score); fclose(fout); return 0; } int findMinlist(STU s[], int n, STU t[]) { int i, k, min_score; min_score = s[0].score; for(i=1; i<n; ++i) if(s[i].score < min_score) min_score = s[i].score; k = 0; for(i=0; i<n; ++i) if(s[i].score == min_score) { t[k]=s[i]; ++k; } return k; }
task5
#include <stdio.h> #include <string.h> #include <stdlib.h> #define N 10 typedef struct { long int id; char name[20]; float objective; float subjective; float sum; char level[10]; } STU; void input(STU s[], int n); void output(STU s[], int n); void process(STU s[], int n); int main() { STU stu[N]; printf("从文件读入%d个考生信息: 准考证号,姓名,客观题得分(<=40),操作题得分(<=60)\n", N); input(stu, N); printf("\n对考生信息进行处理: 计算总分,确定等级\n"); process(stu, N); printf("\n打印考生完整信息, 并保存到文件中"); output(stu, N); return 0; } void input(STU s[], int n) { int i; FILE *fin; fin = fopen("examinee.txt", "r"); if (fin == NULL) { printf("fail to open file\n"); exit(0); } while (!feof(fin)) { for (i = 0; i < n; i++) fscanf(fin, "%ld %s %f %f", &s[i].id, s[i].name,&s[i].objective, &s[i].subjective); } fclose(fin); } void output(STU s[], int n) { FILE *fout; int i; printf("\n"); printf("准考证号\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n"); for (i = 0; i < n; i++) printf("%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); fout = fopen("result.txt", "w"); if (!fout) { printf("fail to open or create result.txt\n"); exit(0); } fprintf(fout, "准考证号\t\t姓名\t客观题得分\t操作题得分\t总分\t\t等级\n"); for (i = 0; i < n; i++) fprintf(fout, "%ld\t\t%s\t%.2f\t\t%.2f\t\t%.2f\t\t%s\n", s[i].id,s[i].name, s[i].objective, s[i].subjective, s[i].sum, s[i].level); fclose(fout); } void process(STU s[], int n) { int i,j; STU t; for(i=0;i<n;i++) { s[i].sum=(s[i].objective)+(s[i].subjective); } for(j=0;j<n-1;j++) for(i=0;i<n-j-1;i++) { if(s[i].sum<s[i+1].sum) { t=s[i]; s[i]=s[i+1]; s[i+1]=t; } } for(i=0;i<1;i++) { strcpy(s[i].level,"优秀"); } for(;i>=i&&i<5;i++) strcpy(s[i].level,"合格"); for(;i<n;i++) { strcpy(s[i].level,"不合格"); } }
task6
#include <stdio.h> #include <stdlib.h> #include <time.h> #define N 80 #define M 5 typedef struct { long int id; char name[20]; char banji[60]; }STU; int main() { int i,j; STU x[N],ran[M]; FILE *fin,*fout; fin = fopen("list.txt","r"); if(fin == NULL) { printf("fail to open list.txt\n"); return 1; } for(i=0;i<N;i++) { fscanf(fin, "%ld %s %s", &x[i].id, x[i].name, x[i].banji); } fclose(fin); srand(time(0)); j = rand()%(80)+1; for(i=0;i<M;i++) { ran[i] = x[j]; j = rand()%(80)+1; } fout = fopen("lucky.txt", "w"); if(fout == NULL) { printf("fail to open file\n"); return 1; } for(i=0;i<M;i++) { fprintf(fout, "%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji); printf("%ld %s %s\n", ran[i].id, ran[i].name, ran[i].banji); } fclose(fout); return 0; }
标签:fp,include,int,char,实验,txt,fin 来源: https://www.cnblogs.com/jwq-niubility/p/16349356.html