#复杂度为n平方
def MaxSubseqSum1(A , N ):
ThisSum=0
MaxSum = 0
for i in range(0,N):
ThisSum=0
for j in range(i,N):

ThisSum=0

for k in range(i,j):

         ThisSum+=A[j]
         if ThisSum>MaxSum:
             MaxSum=ThisSum
 print( MaxSum)    

A=[ -2, 11, -4, 13, -5, -2 ]
N=len(A)
t= MaxSubseqSum1(A , N )

#复杂度更低 n 在线处理

def MaxSubseqSum1(A , N ):
ThisSum=0
MaxSum = 0
for i in range(0,N):
ThisSum+=A[i]

      if ThisSum>MaxSum:
             MaxSum=ThisSum
      elif ThisSum<0:
          ThisSum=0
 print( MaxSum)    

A=[ -1, 3, -2, 4, -6, 1,6,-1 ]
N=len(A)
t= MaxSubseqSum1(A , N )

标签：MaxSubseqSum1,子列,复杂度,0for,range,ThisSum,MaxSum,最大
来源： https://blog.51cto.com/13930723/2362589