MyMath五种方法

package counter;
class MyAdd implements IAdd{
    @Override
    public int add(int num1, int num2) {
        return num1 + num2;
    }
}
class MySub implements ISub{
    @Override
    public int sub(int num1, int num2) {
        return num1 - num2;
    }
}

public class Start {
    public static void main(String[] args) {
        //方法一
        int add = MyMath1.add(1,2,3,4,5);
        int sub = MyMath1.sub(10,5,4,1);
        System.out.println("add="+add);
        System.out.println("sub="+sub);
        System.out.println("--------------------");
        //方法二
        MyMath2 myMath2 = new MyMath2(4,6);
        System.out.println("加法"+myMath2.add());
        System.out.println("减法"+myMath2.sub());
        System.out.println("--------------------");
        //方法三
        MyMath3 myMath3 = new MyMath3();
        int sum1 = myMath3.add(1,2);
        int sum2 = myMath3.sub(2,1);
        System.out.println("接口实现加法="+sum1);
        System.out.println("接口实现减法="+sum2);
        System.out.println("--------------------");
        //方法四
        MyAdd myAdd = new MyAdd();
        MySub mySub = new MySub();
        MyMath4 myMath4 = new MyMath4(myAdd,mySub);
        System.out.println("组合编程加法1="+myMath4.add(5,5));
        System.out.println("组合编程减法1="+myMath4.sub(5,5));
        System.out.println("--------------------");
        //方法五
        MyMath5 myMath5 = new MyMath5(myAdd,mySub);
        System.out.println("组合编程加法2="+myMath5.add(5,5));
        System.out.println("组合编程减法2="+myMath5.sub(5,5));
        System.out.println("--------------------");
    }
}

package counter;

public class MyMath1 {
    public MyMath1(){}
    public static int add(int...data){
        int sum = 0;
        for (int i=0;i<data.length;i++){
            sum += data[i];
        }
        return sum;
    }
    public static int sub(int...data){
        int sum =data[0];
        for (int i=1;i< data.length;i++){
            sum -= data[i];
        }
        return sum;
    }
}

package counter;

public class MyMath2 {
    private int num1,num2;
    public MyMath2(){}
    public MyMath2(int num1,int num2){
        this.num1 = num1;
        this.num2 = num2;
    }
    public int add(){
        int sum;
        sum = num1 + num2;
        return sum;
    }
    public int sub(){
        int sum;
        sum = num1 - num2;
        return sum;
    }
}

package counter;

public class MyMath3 implements IAdd, ISub {
    public MyMath3(){}

    @Override
    public int add(int num1,int num2) {
        return num1 + num2;
    }

    @Override
    public int sub(int num1,int num2) {
       return num1 - num2;
    }
}
interface IAdd {
    int add(int num1,int num2);
}
interface ISub {
    int sub(int num1,int num2);
}

package counter;

public class MyMath4 implements IAdd,ISub {
   private IAdd addMember;
   private ISub subMember;
   public MyMath4(){}
   public MyMath4(IAdd addMember,ISub subMember){
       this.addMember = addMember;
       this.subMember = subMember;
   }

    @Override
    public int add(int num1, int num2) {
        return this.addMember.add(num1, num2);
    }

    @Override
    public int sub(int num1, int num2) {
        return this.subMember.sub(num1, num2);
    }
}

package counter;

public class MyMath5 {
    private IAdd addMember;
    private ISub subMember;
    public MyMath5(){}
    public MyMath5(IAdd addMember,ISub subMember){
        this.addMember = addMember;
        this.subMember = subMember;
    }
    public int add(int num1,int num2){
        return num1 + num2;
    }
    public int sub(int num1,int num2){
        return  num1 - num2;
    }
}

标签：num1,MyMath,int,add,五种,num2,方法,public,sub
来源： https://www.cnblogs.com/AMTK404/p/16307026.html