GSL 求导数:gsl_deriv_central
作者:互联网
GSL 手册里有函数说明和使用范例,函数说明如下:
int gsl_deriv_central(const gsl_function * f, double x, double h, double * result, double * abserr)
This function computes the numerical derivative of the function f at the point x using an adaptive central
difference algorithm with a step-size of h. The derivative is returned in result and an estimate of its absolute
error is returned in abserr.
The initial value of h is used to estimate an optimal step-size, based on the scaling of the truncation error and
round-off error in the derivative calculation. The derivative is computed using a 5-point rule for equally spaced
abscissae at x − h, x − h/2, x, x + h/2, x + h, with an error estimate taken from the difference between the
5-point rule and the corresponding 3-point rule x − h, x, x + h. Note that the value of the function at x does not
contribute to the derivative calculation, so only 4-points are actually used.
下面是手册里的示范代码:
#include <stdio.h>
#include <gsl/gsl_math.h>
#include <gsl/gsl_deriv.h>
double f (double x, void * params)
{
(void)(params); /* avoid unused parameter warning */
return pow (x, 1.5);
}
int
main (void)
{
gsl_function F;
double result, abserr;
F.function = &f;
F.params = 0;
printf ("f(x) = x^(3/2)\n");
gsl_deriv_central (&F, 2.0, 1e-8, &result, &abserr);
printf ("x = 2.0\n");
printf ("f'(x) = %.10f +/- %.10f\n", result, abserr);
printf ("exact = %.10f\n\n", 1.5 * sqrt(2.0));
gsl_deriv_forward (&F, 0.0, 1e-8, &result, &abserr);
printf ("x = 0.0\n");
printf ("f'(x) = %.10f +/- %.10f\n", result, abserr);
printf ("exact = %.10f\n", 0.0);
return 0;
}
~
存为 test_gsl_deriv_central.cpp, 然后编译运行:
g++ test_gsl_deriv_central.cpp -lgsl -lgslcblas
./a.out
得到结果:
f(x) = x^(3/2)
x = 2.0
f'(x) = 2.1213203120 +/- 0.0000005006
exact = 2.1213203436
x = 0.0
f'(x) = 0.0000000160 +/- 0.0000000339
exact = 0.0000000000
标签:%.,central,deriv,double,GSL,abserr,result,printf,gsl 来源: https://www.cnblogs.com/luyi07/p/16280456.html