[AcWing 844] 走迷宫
作者:互联网
BFS 使用STL中的queue
点击查看代码
#include<iostream>
#include<cstring>
#include<queue>
using namespace std;
typedef pair<int, int> PII;
const int N = 100 + 10;
int n, m;
int g[N][N], d[N][N];
queue<PII> q;
int bfs()
{
q.push({0, 0});
memset(d, -1, sizeof(d));
d[0][0] = 0;
int dx[4] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
while (q.size()) {
PII t = q.front();
q.pop();
for (int i = 0; i < 4; i ++) {
int x = t.first + dx[i], y = t.second + dy[i];
if (x >= 0 && x < n && y >= 0 && y < m && g[x][y] == 0 && d[x][y] == -1) {
d[x][y] = d[t.first][t.second] + 1;
q.push({x, y});
}
}
}
return d[n - 1][m - 1];
}
int main()
{
cin >> n >> m;
for (int i = 0; i < n; i ++)
for (int j = 0; j < m; j ++)
cin >> g[i][j];
cout << bfs() << endl;
return 0;
}
BFS 数组模拟队列
点击查看代码
#include<iostream>
#include<cstring>
using namespace std;
typedef pair<int, int> PII;
const int N = 100 + 10;
int n, m;
int g[N][N], d[N][N];
PII q[N * N];
int bfs()
{
int hh = 0, tt = 0;
q[0] = {0, 0};
memset(d, -1, sizeof(d));
d[0][0] = 0;
int dx[4] = {-1, 0, 1, 0}, dy[4] = {0, 1, 0, -1};
while (hh <= tt) {
PII t = q[hh ++];
for (int i = 0; i < 4; i ++) {
int x = t.first + dx[i], y = t.second + dy[i];
if (x >= 0 && x < n && y >= 0 && y < m && g[x][y] == 0 && d[x][y] == -1) {
d[x][y] = d[t.first][t.second] + 1;
q[++ tt] = {x, y};
}
}
}
return d[n - 1][m - 1];
}
int main()
{
cin >> n >> m;
for (int i = 0; i < n; i ++)
for (int j = 0; j < m; j ++)
cin >> g[i][j];
cout << bfs() << endl;
return 0;
}
标签:PII,844,int,迷宫,cin,++,&&,include,AcWing 来源: https://www.cnblogs.com/wKingYu/p/16223093.html