面试题:约瑟夫环
作者:互联网
为初始化每次删除node后的位置,将需要删除的node前的节点后移,从而完成位置初始化。
Python:
class Solution: def LastRemaining_Solution(self , n: int, m: int) -> int: # write code here res=[i for i in range(n)] while len(res)>1: for i in range(m-1): res.append(res.pop(0)) res.pop(0) return res[0]
标签:node,面试题,int,res,Solution,pop,约瑟夫,range 来源: https://www.cnblogs.com/tiuyoaix/p/16221031.html