传递闭包
作者:互联网
传递闭包模板
#include<iostream>
#define maxn 10007
using namespace std;
int a[maxn], dis[107][107], n, m;
int main(void)
{
ios::sync_with_stdio(false);
cin.tie(0); cout.tie(0);
cin >> n;
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
cin >> dis[i][j];
for (int k = 1; k <= n; k++)
for (int i = 1; i <= n; i++)
for (int j = 1; j <= n; j++)
dis[i][j] = dis[i][j] | (dis[i][k] & dis[k][j]);
for (int i = 1; i <= n; i++)
{
for (int j = 1; j <= n; j++)
cout << dis[i][j] << ' ';
cout << endl;
}
return 0;
}
标签:闭包,int,cin,传递,maxn,tie,107 来源: https://www.cnblogs.com/xqk0225/p/16217318.html