pyspark中将数据从列表转换为字符串

初始的DataFrame：

from pyspark.sql.types import StructType, StructField
schema = StructType([StructField("uuid",IntegerType(),True),StructField("test_123",ArrayType(StringType(),True),True)])
rdd = sc.parallelize([[1, ["test","test2","test3"]], [2, ["test4","test","test6"]],[3,["test6","test9","t55o"]]])
df = spark.createDataFrame(rdd, schema)

df.show()
+----+--------------------+
|uuid|            test_123|
+----+--------------------+
|   1|[test, test2, test3]|
|   2|[test4, test, test6]|
|   3|[test6, test9, t55o]|
+----+--------------------+

使用udf自定义一个连接列表的方法：

from pyspark.sql.functions import udf, col
# join是python中自带的方法，用于返回一个以分隔符sep连接各个元素后生成的字符串
join_udf = udf(lambda x: ",".join(x))
df.withColumn("test_123", join_udf(col("test_123"))).show()

+----+----------------+
|uuid|        test_123|
+----+----------------+
|   1|test,test2,test3|
|   2|test4,test,test6|
|   3|test6,test9,t55o|
+----+----------------+

标签：t55o,join,test6,pyspark,列表,test,123,udf,字符串
来源： https://www.cnblogs.com/Ao0216/p/16194505.html