比较两个新旧字符串数组

/**
 * 比较两个新旧字符串数组
 * @param oldArr 旧数组
 * @param newArr 新数组
 * @return Map 包含两个数组，相较于旧数组，新数组多了哪些元素，少了哪些元素
 */
public static Map<String,String[]> stringArrayCompare(String[] oldArr, String[] newArr){
    List<String> addList = new ArrayList<>();
    List<String> deleteList = new ArrayList<>();
    for (String anOldArr:oldArr){
        if(!ArrayUtils.contains(newArr,anOldArr)){
            deleteList.add(anOldArr);
        }
    }

    for (String aNewArr:newArr){
        if(!ArrayUtils.contains(oldArr,aNewArr)){
            addList.add(aNewArr);
        }
    }

    String[] addArr =  addList.toArray(new String[addList.size()]);
    String[] deleteArr =  deleteList.toArray(new String[deleteList.size()]);
    Map<String,String[]> res = new HashMap<>();
    res.put("addArr",addArr);
    res.put("deleteArr",deleteArr);
    return res;
}

标签：String,addList,res,新旧,数组,字符串,new,oldArr
来源： https://www.cnblogs.com/mmady/p/16191207.html