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leetcode 587 安装栅栏

作者:互联网

class Solution {
public:
    int getarea(vector<int>& a, vector<int>& b, vector<int>& c){
        int x1 = b[0] - a[0], y1 = b[1] - a[1], x2 = c[0] - a[0], y2 = c[1] - a[1];
        return x1 * y2 - x2 * y1;
    }
    vector<vector<int>> outerTrees(vector<vector<int>>& trees) {
        int n = trees.size(), pos = 1;
        vector<vector<int>> ans;
        vector<int> dp(n + 5), vis(n + 1);
        sort(trees.begin(), trees.end(), [](vector<int>& a, vector<int>& b){
            return a[0] == b[0] ? a[1] <= b[1] : a[0] <= b[0];
        });
        for(int i = 1; i < n; i++){
            while(pos >= 2){
                if(getarea(trees[dp[pos - 2]], trees[dp[pos - 1]], trees[i]) < 0){
                    vis[dp[pos - 1]] = 0; pos--;
                }else break;
            }
            dp[pos++] = i; vis[i] = 1;
        }
        int len = pos;
        for(int i = n - 1; i >= 0; i--){
            if(vis[i]) continue;
            while(pos >= len + 1){
                if(getarea(trees[dp[pos - 2]], trees[dp[pos - 1]], trees[i]) < 0){
                    vis[dp[pos - 1]] = 0; pos--;
                }else break;
            }
            dp[pos++] = i;
        }
        for(int i = 0; i < pos - 1; i++){ // 起始点会被重复加入
            ans.push_back(trees[dp[i]]);
        }
        return ans;
    }
};

标签:587,栅栏,int,pos,trees,vis,vector,leetcode,dp
来源: https://www.cnblogs.com/shinianhuanniyijuhaojiubujian/p/16182637.html