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三天打鱼两天晒网

作者:互联网

/*
Date: 11/03/19 11:04
Description: 三天打鱼两天晒网
*/
#include<stdio.h>

int sumDate(int year,int month,int day);
bool judge(int sumday);
bool leap(int year);

int main(void)
{
  int year,month,day,sumday;
  bool flag;

  printf("请输入今天的日期:\n");
  scanf("%d%d%d",&year,&month,&day);
  sumday=sumDate(year,month,day);
  flag=judge(sumday);
  if(flag==true)
    printf("%d-%d-%d,今天该打鱼!",year,month,day);
  else
    printf("%d-%d-%d,今天该晒网!",year,month,day);

  return 0;
}
bool leap(int year)//该函数用于判断是否为闰年
{
  bool lep=false;
  if(year%4==0&&year%100!=0||year%400==0)//判断闰年
    lep=true;
  return lep;
}
int sumDate(int year,int month,int day)//该函数用于求总天数
{
  int year1=1990,month1=1,day1=1;//起始年-月-日
  int count=0;//统计该年以前闰年年份数
  int passday=0;//过去年份的总天数
  int nowday=0;//当前年份的总天数
  int sumday=0;//统计总天数
  int mon[]={31,28,31,30,31,30,31,31,30,31,30,31};//每月对应的天数

  for(year1;year1<year;year1++)
  {
    passday+=365;//每一年先按照365天算
    if(leap(year1)==true)
      count++;//是闰年count+1
  }
  passday=passday+count;
  printf("前面年份的天数=%d\n",passday);

  for(int i=0;i<month-1;i++)
    nowday+=mon[i];
  nowday=nowday+day;
  if(leap(year)==true&&month>=3)
  {
    nowday+=1;
  }
  printf("今年的天数=%d\n",nowday);
  sumday=passday+nowday;
  printf("总天数=%d\n",sumday);
  return sumday;
}
bool judge(int sumday)//该函数用于判断打鱼还是晒网
{
  bool flag;
  switch(sumday%5)
  {
    case 1://1、2、3天打鱼flag置为true
    case 2:
    case 3:
      flag=true; break;
    case 0://4、5天晒网flag置为false
    case 4:
      flag=false; break;
    default: break;
  }
  return flag;
}

【运行结果】

 

标签:三天打鱼,两天晒网,int,sumday,month,flag,year,day
来源: https://www.cnblogs.com/sinlearn/p/10510083.html